Answer:
radio waves, microwaves, infrared, visible, UV, X-rays, gamma rays
Explanation:
Electromagnetic waves consist of oscillating electric and magnetic fields which vibrate in a direction perpendicular to the direction of motion of the wave (transverse wave). Electromagnetic waves travel in a vacuum with a speed of (speed of light), and they are classified into 7 different types according to their wavelength.
From longer to shorter wavelength, these types are:
Radio waves (wavelength > 30 cm)
Microwaves (30 cm - )
Infrared ()
Visible light (750 nm - 380 nm)
UV radiation (380 nm - 8 nm)
X-rays (8 nm - 6 pm)
Gamam rays (< 6 pm)
Answer:
162500000.
Explanation:
Given that
Diameter of the wire , d= 1.8 mm
The length of the wire ,L = 15 cm
Current ,I = 260 m A
The charge on the electron ,e= 1.6 x 10⁻¹⁹ C
We know that Current I is given as
I=Current
q=Charge
t=time
q= I t
q= 260 m t
The total number of electron = n
q= n e
n=162500000 t
The number of electron passe per second will be 162500000.
Answer:
ΔR = 5 s
Explanation:
The absolute uncertainty or error in an expression is
ΔR = | | ΔB + | | ΔA
the absolute value guarantees to take the unfavorable case, that is, the maximum error.
We look for the derivatives
= 1
= -1
we substitute
ΔR = 1 ΔB + 1 ΔA
of the data
ΔB = 3 s
ΔA = 2 s
ΔR = 3 + 2
ΔR = 5 s
If a gun is sighted to hit targets that are at the same height as the gun and 85 m away at the same height, how low, as a positive number in meters, will the bullet hit if aimed directly at a target 180 m away
The muzzle velocity of the bullet is 275 m/s
Answer:
y = -1.1109 m
Explanation:
Range =
range = 85 m
velocity = 275 m/s
g = 9.8 m/s²
If the bullet is aimed at a target 180 m, time required to travel 180 m with horizontal component will be;
t = 0.6546 sec
To determine, how low as a positive number in meters.
y =
y = 0.9909 - 2.1018
y = -1.1109 m