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anastassius [24]
3 years ago
12

A car traveling with constant speed travel 150 km in 7200s.what is the speed of the car?

Physics
1 answer:
scoray [572]3 years ago
6 0
Time = 7200 s.              3600 s = 1hour.

7200s = 7200 / 3600 = 2 hours.

Speed = Distance / time  =  150 km / 2 hours =  75 km/h
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A thin uniform rod of mass M and length L is bent at its center so that the two segments are now perpendicular to each other. Fi
Tatiana [17]

Answer:

(a) I_A=1/12ML²

(b) I_B=1/3ML²

Explanation:

We know that the moment of inertia of a rod of mass M and lenght L about its center is 1/12ML².

(a) If the rod is bent exactly at its center, the distance from every point of the rod to the axis doesn't change. Since the moment of inertia depends on the distance of every mass to this axis, the moment of inertia remains the same. In other words, I_A=1/12ML².

(b) The two ends and the point where the two segments meet form an isorrectangle triangle. So the distance between the ends d can be calculated using the Pythagorean Theorem:

d=\sqrt{(\frac{1}{2}L) ^{2}+(\frac{1}{2}L) ^{2} } =\sqrt{\frac{1}{2}L^{2} } =\frac{1}{\sqrt{2} } L=\frac{\sqrt{2} }{2} L

Next, the point where the two segments meet, the midpoint of the line connecting the two ends of the rod, and an end of the rod form another rectangle triangle, so we can calculate the distance between the two axis x using Pythagorean Theorem again:

x=\sqrt{(\frac{1}{2}L)^{2}-(\frac{\sqrt{2}}{4}L)  ^{2} } =\sqrt{\frac{1}{8} L^{2} } =\frac{1}{2\sqrt{2}} L=\frac{\sqrt{2}}{4} L

Finally, using the Parallel Axis Theorem, we calculate I_B:

I_B=I_A+Mx^{2} \\\\I_B=\frac{1}{12} ML^{2} +\frac{1}{4}  ML^{2} =\frac{1}{3} ML^{2}

5 0
2 years ago
A 7 kg object attached to a horizontal string moves with constant speed in a circle on a frictionless horizontal surface. The ki
Marizza181 [45]

Answer:

Explanation:

Given

mass of object m=7 kg

kinetic Energy k=36\ J

Tension in string T=326\ N

mass is moving in a horizontal circle so tension is providing the centripetal acceleration

therefore T=\frac{mv^2}{r}----1

where r=radius of circle

kinetic energy of particle k=\frac{1}{2}mv^2----2

divide 1 and 2 we get

\frac{T}{k}=\frac{\frac{mv^2}{r}}{\frac{1}{2}mv^2}

\frac{T}{k}=\frac{2}{r}

r=\frac{2k}{T}=\frac{2\times 36}{326}

r=0.2208\ m

   

8 0
3 years ago
Why would Sodium(Na) and Chlorine (CI) want to form a lonic Bond?
miskamm [114]

Answer: to achieve a stable octet of electrons in their outer shell

Explanation:

- Sodium (Na) has an atomic number of 11, and an electronic configuration of 1s2, 2s2 2p6, 3s1.

- Chlorine (CI) Sodium (Na) has an atomic number of 17, and an electronic configuration of 1s2, 2s2 2p6, 3s2 3p5.

Hence, sodium donates its single valence electron to chlorine, thereby achieving a stable octet structure of 1s2, 2s2 2p6 while chlorine accept the single electron also forming a stable octet structure of 1s2, 2s2 2p6, 3s2 3p6. Therefore, the reaction yields NaCl, an ionic compound with ionic (electrovalent) bond.

Na + Cl --> NaCl

Thus, Sodium(Na) and Chlorine (CI) want to form a lonic Bond because both acheive a completely filled outermost shell (octet structure)

3 0
3 years ago
Which one is correct and why?​
Gelneren [198K]

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'A' is the correct way to hook everything up.

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So each time you come to any device in the circuit ... whether it's a resistor or a meter ... you would be hitting the positive side of it first, and then the voltage where you come out on the other side of it would be lower.  

So the left side of the resistor is more positive, and the right side is more negative.  The voltmeter is connected correctly in 'A', but it's backwards in 'C'.  If you connect the voltmeter like in 'C' and turn things on, the voltmeter will try  to go <em>down</em> from zero.  You can't read the number on it, and It's possible that the voltmeter might be damaged.  

6 0
3 years ago
How much does a 725 kg<br> elevator weigh?<br> F = [?]N
olga2289 [7]
725 Kg equals 725x9.8= 7105 N
8 0
3 years ago
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