Answer:
Work done, W = 1.44 kJ
Explanation:
Given that,
Mass of boy, m = 74 kg
Initial speed of boy, u = 1.6 m/s
The boy then drops through a height of 1.56 m
Final speed of boy, v = 8.5 m/s
To find,
Non-conservative work was done on the boy.
Solution,
The work done by the non conservative forces is equal to the sum of total change in kinetic energy and total change in potential energy.
W = 1447.21 Joules
or
W = 1.44 kJ
Therefore, the non conservative work done on the boy is 1.44 kJ.
2026.8678
first well then you align the decimals together and then go down like you normally do
The speed of the vehicle after the push is 2.7 m/s.
<h3>What is velocity?</h3>
velocity is the rate of change of displacement.
To calculate the velocity of the vehicle, we use the formula below.
Formula:
- v = √[2(W-W')/m]............... Equation 1
Where:
- W = work done by the pusher
- W' = Work done by friction
- m = mass of the car
From the question,
Given:
- W = 6500 J
- W' = 2000 J
- m = 1200 kg
Substitute these values into equation 1
- v = √[2(6500-2000)/1200]
- v = √(7.5)
- v = 2.7 m/s
Hence, the speed of the vehicle after the push is 2.7 m/s.
Learn more about velocity here:
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