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Komok [63]
3 years ago
9

Pls help I’m being timed!!

Physics
2 answers:
Firdavs [7]3 years ago
6 0

Answer:

B

Explanation:

Heat increase molecular motion

Rzqust [24]3 years ago
3 0

Answer:

B

Explanation:

The more motion there is in the molecules, the more thermal energy is absorbed.

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How far does a sled travel in 5 seconds while accelerating from 4 m/s to 10 m/s?
mina [271]

Answer:

All we need to know for this is SUVAT equations. There are 5 SUVAT equations you need to learn. S = distance, U = initial velocity, V = final velocity, A = acceleration, T = time V= U + AT V^2 = U^2 + 2AS S = UT + 1/2AT^2 S = VT -

Explanation:

don't now if this hellps or not

3 0
3 years ago
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A solid sphere is rolling on a surface. what fraction of its total kinetic energy is in the form of rotational kinetic energy ab
drek231 [11]
<span>Total KE = KE (rotational) + KE (translational) Moment of inertia of sphere is I = (2/5)mr^2 So KE (rotational) = (1/2) x I x w^2 = (1/2) x (2/5)mr^2 x w^2 = (1/5) x m x r^2 x w^2 KE (translational) = (1/2) x m x v^2 = (1/2) x m x (rw)^2 = (1/2) x m x r^2 x w^2 Hence KE = (1/5) x m x r^2 x w^2 + (1/2) x m x r^2 x w^2 = m x r^2 x w^2 ((1/5) + (1/2)) KE = (7/10) m x r^2 x w^2 Calculating the fraction of rotational kinetic energy to total kinetic energy, = rotational kinetic energy / total kinetic energy = (1/5) x m x r^2 x w^2 / (7/10) m x r^2 x w^2 = (1/5) / (7/10) = 2 / 7 The answer is 2 / 7</span>
7 0
3 years ago
A model that shows the many interconnected feeding relationships in an ecosystem is a food .
arlik [135]

Answer:

Since ecosystems contain many different species of animals, plants, and other organisms, consumers have a variety of food sources. The pattern of feeding represented by these interconnected and branching food chains is called a food web. Figure 36-3 shows how food chains within a food web are interconnected.

Explanation:

4 0
3 years ago
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Name the colors of visible light beginning with that of lowest energy (longest wavelength)
lions [1.4K]
Red, Orange, Yellow, Green, Blue, Indigo, Violet.

Remember ROYGBIV.
3 0
3 years ago
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To initiate a nuclear reaction, an experimental nuclear physicist wants to shoot a proton into a 5.50-fm-diameter 12C nucleus. T
Fantom [35]

Answer:

V_1= 3.4*10^7m/s

Explanation:

From the question we are told that

Nucleus diameter d=5.50-fm

a 12C nucleus

Required kinetic energy K=2.30 MeV

Generally initial speed of proton must be determined,applying the law of conservation of energy we have

            K_2 +U_2=K_1+U_1

where

K_1 =initial kinetic energy

K_2 =final kinetic energy

U_1 =initial electric potential

U_2 =final electric potential

mathematically

   U_2 = \frac{Kq_pq_c}{r_2}

where

r_f=distance b/w charges

q_c=nucleus charge =6(1.6*10^-^1^9C)

K=constant

q_p=proton charge

Generally kinetic energy is know as

         K=\frac{1}{2}  mv^2

Therefore

         U_2 = \frac{Kq_pq_c}{r_2} + K_2=\frac{1}{2}  mv_1^2 +U_1

Generally equation for radius is d/2

Mathematically solving for radius of nucleus

         R=(\frac{5.50}{2}) (\frac{1*10^-^1^5m}{1fm})

         R=2.75*10^-^1^5m

Generally we can easily solving mathematically substitute into v_1

   q_p=6(1.6*10^-^1^9C)

   K_1=9.0*10^9 N-m^2/C^2

   U_1= 0

   R=2.75*10^-^1^5m

   K=2.30 MeV

   m= 1.67*10^-^2^7kg

   V_1= (\frac{2}{1.67*10^-^2^7kg})^1^/^2 (\frac{(9.0*10^9 N-m^2/C^2)*(6(1.6*10^-^1^9C)(1.6*10^-^1^9C)}{2.75*10^-^1^5m+2.30 MeV(\frac{1.6*10^-^1^3 J}{1 MeV}) }

    V_1= 3.4*10^7m/s

Therefore the proton must be fired out with a speed of V_1= 3.4*10^7m/s

8 0
3 years ago
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