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DanielleElmas [232]
3 years ago
7

which of the following laboratory tool would be most appropiate for measuring the approximate volume of a liquid?

Physics
1 answer:
SIZIF [17.4K]3 years ago
7 0
Beaker would be most appropriate for measuring the approximate volume of a liquid.
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Select all that apply.
lutik1710 [3]

Answer: Virtual, upright and diminished.

Explanation:

A transparent material that focuses or diverges light is known as a lens. There are mainly two types of lens: concave lens and convex lens. Other lens can be made using combination of these two and plane one.

A concave lens is a diverging lens. It means the light from any real object after passing through this lens appears to diverge from the focus. A image formed by a diverging lens is virtual, upright and diminished.


4 0
3 years ago
Read 2 more answers
How does fungi, snails, earthworms, and pill bugs return nutrients to the ecosystem?
luda_lava [24]
They decompose and leave their nutrients in the earth. 
4 0
4 years ago
Which two statements are scientific claims?
slavikrds [6]

Answer:

c.an equation that can be used to accurately calculate the pull of gravity between two objects

Explanation:

umm ok for you

6 0
3 years ago
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Two resistors A and B are arranged in series in one branch of a parallel arrangement. The other branch contains a single resisto
Ganezh [65]

Answer:

Explanation:

A and B are in series , Total resistance = Ra + Rb

This resistance is in parallel with single resistor C

Equivalent resistance Re = Rc x ( Ra + Rb ) / [Rc + ( Ra + Rb )]

Now this combination is in series in single resistance D .

Total resistance = Rd + Re

= Rd + { Rc x ( Ra + Rb ) / [Rc + ( Ra + Rb )] }

5 0
3 years ago
Let's apply Snell's law to the refraction of light across a water–air interface. Suppose you kneel beside the fishpond in your b
Nataliya [291]

Answer:

The angle of refraction is 41.68°.

Explanation:

The refractive index for water is n_2 = 1.333, and for air n_1 = 1.00: the angle of light with the normal is 90^o-60^o = 30^o; therefore Snell's law gives

n_1sin(\theta_1)= n_2sin(\theta_2)

1.00*sin(\theta_1) = 1.33 sin(30^o)

sin (\theta_1) = \dfrac{1.33sin(30^o)}{1.00}

sin (\theta_1) = 0.665

\theta _1 = sin^{-1}(0.665)

\boxed{\theta_1 = 41.68^o}

4 0
3 years ago
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