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DanielleElmas [232]
3 years ago
7

which of the following laboratory tool would be most appropiate for measuring the approximate volume of a liquid?

Physics
1 answer:
SIZIF [17.4K]3 years ago
7 0
Beaker would be most appropriate for measuring the approximate volume of a liquid.
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7. Jake is bowling with a 8 kg bowling ball. He rolls the ball at 7 m/s, and it hits one stationary pin with a mass of 2 kg. The
Anna007 [38]
This is a conservation of momentum problem. Initial momentum must equal final momentum. 
Momentum= mass* velecoity
I will denote Ball as b and pin as p
Initial momentum= V(initial b)* Mass(b)+ V(initial p) *mass (p)
since the pin is stationary to begin that means velocity is 0 and we can plug in for the rest
Initial momentum= 7m/s*8kg=56 mkg/s
Now for final momentum=V(final b)*mass(b)+V(final p)*mass(p) plugin
final momentum=V(final b)*8kg+12m/s*2kg
we can set final momentum= inital momentum and solve for V(final b)
56mkg/s= V(final b)*8kg+ 24mkg/s
32mkg/s=V(final b)*8kg
4m/s=V(final b)
so 4 meters/second is the answer


7 0
3 years ago
What is the luster of talc
GarryVolchara [31]

Talc is usually green, white, gray, brown, or colorless. It is a translucent mineral with a pearly luster. It is the softest known mineral and is assigned a hardness of 1 on the Mohs Hardness scale. Talc is a mono clinic mineral with a sheet structure similar to the mica's.

4 0
3 years ago
A 1.0 m length of metal wire is connected to a battery, and a current of flows through it. What is the diameter of the wire? The
Anuta_ua [19.1K]
Nice ! This could be a dynomite exercise if we only knew the voltage of the battery, the current, and the resistivity.
6 0
3 years ago
What happens to a gas that is enclosed in a rigid container when the temperature of the gas is increased?
kiruha [24]
A. the gas particles move faster and collide more frequently, which causes an increase in pressure.

Increasing temperature increases the energy of the gas, which causes the kinetic energy of the molecules to increase.
4 0
3 years ago
A 3.0-kg object moves to the right with a speed of 2.0 m/s. It collides in a perfectly elastic collision with a 6.0-kg object mo
Zinaida [17]

Answer:

The kinetic energy of the system after the collision is 9 J.

Explanation:

It is given that,

Mass of object 1, m₁ = 3 kg

Speed of object 1, v₁ = 2 m/s

Mass of object 2, m₂ = 6 kg

Speed of object 2, v₂ = -1 m/s (it is moving in left)

Since, the collision is elastic. The kinetic energy of the system before the collision is equal to the kinetic energy of the system after the collision. Let it is E. So,

E=\dfrac{1}{2}m_1v_1^2+\dfrac{1}{2}m_2v_1^2

E=\dfrac{1}{2}\times 3\ kg\times (2\ m/s)^2+\dfrac{1}{2}\times 6\ kg\times (-1\ m/s)^2

E = 9 J

So, the kinetic energy of the system after the collision is 9 J. Hence, this is the required solution.

3 0
3 years ago
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