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4 years ago

Do you know the answer to this question?

Chemistry

1 answer:

Yakvenalex [24]4 years ago

6 0

Yes i do know what this question is.

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Copper and silver are two examples of atoms that will form a(n)

Airida [17]

Answer:

covalent bond is the answer

6 0

3 years ago

How many moles of solute are present in 150mL of 0.30 mol/L NaOH solution

Sati [7]

Answer: n= 0.045 mol

Explanation: amount of substance in moles is n= cV= 0.30 mol/l· 0.150 l

6 0

3 years ago

The heat capacity of water is 1cal degree'g1 (1 calorie per degree centigrade, per gram). You are given 1 gallon of water at 25

sdas [7]

Answer:

The heat needed to boil 1 gallon of water is 81,490.62 Joules.

Explanation:

$Q=mc\Delta T$

Where:

Q = heat absorbed or heat lost

c = specific heat of substance

m = Mass of the substance

ΔT = change in temperature of the substance

We have :

Volume of water = V = 1 gal = 4546.09 mL

Density of water , d= 1 g/mL

mass of water = m = d × V = 1g/mL × 4546.09 mL = 4546.09 g

Specific heat of water = c = 1 Cal/g°C

ΔT = 100°C - 25°C = 75 °C

9 (boiling pint of water is 100°C)

Heat absorbed by the water to make it boil:

$Q= 4546.09 g\times 1 Cal/g^oC\times 75^oC=340,956.75 Cal$

1 calorie = 4.184 J

$Q=\frac{340,956.75}{4.184} J = 81,490.62 J$

The heat needed to boil 1 gallon of water is 81,490.62 Joules.

5 0

3 years ago

The gravitational pull of the Moon has the greatest influence on the water levels of Earth’s ocean tides. If the distance betwee

kherson [118]

The water levels would lower, because as the moon gets farther away, it's gravitational pull decreases. Hope this helps! :)

6 0

3 years ago

The half-life of tritium is 12.3 years. If 48.0 mg of tritium is released from a nuclear power plant during the course of a mish

Thepotemich [5.8K]

Half life is defined as the time when the final concentration reduced to half of the initial value.

Thus, for first half life, the remaining percentage of the reactant is 50 percent that is $\frac{50}{100}=\frac{1}{2}$

Now, for second half life, the remaining percentage will be 50 percent of the remaining 50 percentage that is $\frac{50}{2}=25$ $\frac{25}{100}=\frac{1}{4}$ or $\frac{1}{2^{2}}$

Thus, general formula for n half lives = $\frac{1}{2^{n}}$

Now, 98.4 years is equal to eighth times 12.3 years that is $\frac{1}{2^{8}}$ = $\frac{1}{256}$ remaining material.

Therefore, mass of the nuclide will remain after 98.4 years= $\frac{48.0 mg}{256}$

= $0.1875 mg$

Mass of remaining nuclide after 98.4 years = $0.1875 mg$

4 0

4 years ago