Explanation
If you graph the force on an object as a function of the position of that object, then the area under the curve will equal the work done on that object, so we need to find the area under the function to find the work
Step 1
find the area under the function.
so
Area:
so
therefore, the answer is
I hope this helps you
This question is incomplete, the missing image uploaded along this answer below;
Answer:
a) frequency is 2.381 Hz
b) the angular frequency/speed is 14.96 rad/s
c) the magnitude of the magnetic field is 0.5199 T
Explanation:
Given that;
cross sectional Area A = 0.018 m²
Number of turns N = 200
from the diagram. maximum time T = 0.42 sec
a) the frequency f of the generator in hertz
frequency = 1 / T
we substitute
frequency = 1 / 0.42 = 2.381 Hz
Therefore, frequency is 2.381 Hz
b) the angular frequency in rad/s
angular speed ω = 2πf
we substitute
ω = 2π × 2.381
ω = 14.96 rad/s
Therefore, the angular frequency/speed is 14.96 rad/s
c) the magnitude of the magnetic field.
to determine the magnitude of the magnetic field, we use the following expression;
e = NBAω
from the diagram, e = 28.0 V
so we substitute
28.0 V = 200 × B × 0.018 × 14.96
28 = 53.856B
B = 28 / 53.856
B = 0.5199 T
Therefore, the magnitude of the magnetic field is 0.5199 T
