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2 years ago

9

A robot probe drops a camera off the rim of a 278 m high cliff on Mars, where the free-fall acceleration is 3.7 m/s2 . Find the

velocity with which it hits the ground. Answer in units of m/s.

1 answer:

FromTheMoon [43]2 years ago

4 0

S = u + at u = 0 278 = 3.7t t = 278/3.7 = 75.135.. v = ut + 0.5at^2 u = 0 v = 0.5 * 3.7 * 75.135^2 = 10,443 m/sec

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Answer:

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The weight ( P = m*g = 10 [kg]*9,8 [m/s²] = 98 [N] negative

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