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Travka [436]
3 years ago
7

How would the absence of gravity affect the formation of planets?

Physics
2 answers:
Doss [256]3 years ago
5 0

Answer : The rocks and debris would never accrete into a planet.

Explanation : Gravity is an attraction force and dependents on the mass of the objects but in the absence of the force the rocks and debris would not come together to form a clump.

So,  we can say that in the absence of gravity, the rock and debris would never accrete into a planet.  

Maru [420]3 years ago
3 0

The correct answer is B. The rocks and debris would never accrete into a planet.

Explanation:

Gravity refers to a force of attraction between objects due to their masses. This force is described through the formula F= G M m/ r2 in which G is equal to the gravitational constant, M and m describe the mass of objects, and r refers to the distance.

Moreover, gravity was essential for the formation of planets, stars and other elements in the universe, because this caused gas, dust, rocks, and other particles or elements to aggregate or accrete into planets and other celestial bodies. Moreover, gravity is responsible for phenomena such as planets orbiting. The previous idea implies that without gravity the formation of planets would not have possible and therefore "the rocks and debris would never accrete into a planet".

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You hear a sound in the distance. Suddenly the sound gets deeper, decreasing in pitch. Which can you assume about the sound wave
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Answer:

A. The wavelengths of the new sound waves are longer

Explanation:

This is the Doppler effect which can be best illustraded  for the case of a siren of an ambulance approaching us having a greater frequency and getting lower in frequency and deeper as the ambulance passes  us.

Since the wavelength is inversely proportional to the frequency it follows the wavelengths are longer when the frequency decreases lowering its pitch and getting deeper.

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You make a capacitor by cutting the 16.0-cm-diameter bottoms out of two aluminum pie plates, separating them by 3.25 mm, and con
dalvyx [7]

Answer:

The capacitance of your capacitor is 5.476 x 10⁻⁵ μF

Explanation:

Given;

diameter of the aluminum pie plates = 16 cm = 0.16 m

separation distance, d = 3.25 mm = 0.00325 m

voltage across the parallel plates = 6 V

C = \frac{\epsilon A}{d}

where;

C is the capacitance of your capacitor

ε is the permittivity of free space = 8.85 x 10⁻¹²  (F/m)

d is separation distance

A is the area of the plate = ¹/₄ (πd²) = 0.25 (π x 0.16²) = 0.02011 m²

C = \frac{8.85*10^{-12} *0.02011}{0.00325} = 5.476 * 10^{-11} \ F = \ 5.476 * 10^{-5} \mu F

Therefore, the capacitance of your capacitor is 5.476 x 10⁻⁵ μF

3 0
3 years ago
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Let us first write down the known things .

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