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Otrada [13]
4 years ago
9

How to type a capital letter in my computer​

Physics
2 answers:
natita [175]4 years ago
7 0

Answer:

Hold down the shift key if your on windows, mac or chromebooks.

Explanation:

Computer Technician

bixtya [17]4 years ago
7 0

Answer:

Press the "caps lock" button and then press which letter u want to be in cap

You might be interested in
Una atracción de feria consiste en lanzar un trineo de 2 kg por una rampa ascendente que forma un ángulo de 30º con la horizonta
Arada [10]

Answer:

La velocidad con la que se debe lanzar el trineo es aproximadamente 9.96 m/s

Explanation:

La masa del trineo, m = 2 kg

El ángulo de inclinación del trineo, θ = 30 °

El coeficiente de fricción, μ = 0,15

La altura a la que debe ascender el trineo, h = 4 m

La reacción normal del trineo en la rampa, N = m · g · cos (θ)

La fuerza de fricción F_f = N × μ

Dónde;

g = Th aceleración debida a la gravedad ≈ 9.81 m/s²

∴ F_f  = 0.15 × 2 kg × 9.81 m/s² × cos (30°) ≈ 2.55 N

La longitud de la rampa que se mueve el trineo, l = h/(sin(θ))

∴ l = 4/(sin(30°)) = 8

La longitud de la rampa que se mueve el trineo, l = 8 m

El trabajo realizado sobre la fricción, W_f = F_f × l

W_f = 2.55 × 8 ≈ 20.4

El trabajo realizado sobre la fricción, W_f ≈ 20.4 Julios

El trabajo realizado para levantar el trineo a 4 metros de altura, P.E. = m·g·h

∴ P.E. = 2 kg × 9.81 m/s² × 4 m ≈ 78.48 Joules

El trabajo realizado para levantar el trineo a 4 metros de altura, P.E. ≈ 78.48 Joules

El trabajo total requerido para levantar el trineo 4 metros por la rampa, W_t = W_f + P.E.

W_t = 20.4 J + 78.84 J ≈ 99.24 J

Energía cinética, K.E. = 1/2 × m × v²

La energía cinética necesaria para mover el trineo por la rampa, K.E. se da de la siguiente manera;

K.E. = 1/2 × 2 kg × v² ≈ 99.24 J

∴ v² ≈ 99.24 J/(1/2 × 2 kg)

La velocidad con la que se debe lanzar el trineo para que ascienda 4 metros por la rampa, v ≈ 9.96 m/s

4 0
3 years ago
10 kg box accelerates at 2 meters per second as it slides down a ramp at an angle of 25 degrees. What is the coefficient of fric
maria [59]

Answer:

0.241

Explanation:

resolving weight into two components and calculating force of friction in terms of coefficient of friction and then applying Newton 's law we get the value .This all has been explained in attachment

Download pdf
3 0
3 years ago
Billy is listening to a conversation through a solid 2 meter thick concrete wall. If it only takes .05 seconds for the conversat
Alex_Xolod [135]

Answer:

0.025 Meters a second, or 0.025 m/s

Explanation:

So, if we take the information that we know, 1) The wall is 2 meters thick, and 2) it took a total of 0.05 seconds to travel all the way. So, to get our answer, lets divide 0.05 by 2. That lands us with 0.025! This answer makes sense, because we know that sound travels quickest in solids, (Due to sound-waves  being a mechanical longitudinal wave, and solids have the densest particle formations, allowing the sound wave to travel swiftly compared to liquids and gases, in which the particles are more spread out.)

6 0
3 years ago
1. Determine the energy released per kilogram of fuel used.
Serga [27]

The formula for energy release per kilogram of fuel burned is energy release per kg=6.702*10-13. and 19. J 1 Mev = 1.602 X 10 T

Calculate the energy in joules per kilogram of reactants given MeV per reaction. Energy is the ability or capacity to perform tasks, such as the ability to move an item (of a certain mass) by exerting force. Energy can exist in many different forms, including electrical, mechanical, chemical, thermal, or nuclear, and it can change its form.
Think of a mole of plutonium-239 (molar mass: 239 grams) as a mole of "reactions."

Energy used in the US per person annually = 3-5 X 1011
Population (number of people) = 3.108The required mass of the fuel is 3.5x1011 x3-1x10 8x 10)/6.703 X1013 kg. the mass required: 1.62 x 1033 kg Mev in Joules 6 is equal to 101.60*I0-
19. J 1 Mev = 1.602 X 10 T, which translates to 1.602*1013/2.39x10-3 energy release per kilogram, or 6.702*10-13.

To learn more about Energy please visit -
brainly.com/question/27671072
#SPJ1

8 0
2 years ago
A scooter is accelerated from rest at the rate of 8m/s . How long will it take to cover a distance of 32m?​
TiliK225 [7]
  • <em>S</em><em>peed </em><em>=</em><em> </em><em>8</em><em> </em><em>m/</em><em>s</em>
  • <em>Distance</em><em> </em><em>=</em><em> </em><em>3</em><em>2</em><em> </em><em>m</em>

<u>We need to find time</u>

<h3>We know that ,</h3>

\begin{gathered} {\underline{\boxed{ \rm {\red{Speed \:  =  \:  \frac{Distance}{Time} }}}}}\end{gathered}

<h3>So ,</h3>

\begin{gathered} {\underline{\boxed{ \rm {\orange{Time \:  =  \:  \frac{Distance}{Speed} }}}}}\end{gathered}

<h3><u>Substuting</u><u> the</u><u> values</u></h3>

\begin{cases} \large\rm{\purple{ {\leadsto} }} \:  \: Time \:  =  \:  \frac{32}{8} \\  \\ \large\rm{\purple{ {\leadsto} }} \:  \: Time \:  =  \:   \cancel\frac{32}{8} \\  \\ \large\rm{\purple{ {\leadsto} }} \:  \: Time \:  =  \:  4 \: seconds \end{cases}

6 0
3 years ago
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