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Natalija [7]
3 years ago
6

Two boxes, P and Q, are at rest on a frictionless horizontal surface. A light, flexible cord connects them. The mass of P is gre

ater than the mass of Q.
(As shown in the diagram,) A horizontal force of magnitude F is applied to box Q, causing both boxes to accelerate to the right.
What best describes the magnitude of the force exerted by the connecting cord on box P?

*equal to F
*greater than F
*zero
*less than F, but greater than zero
Physics
2 answers:
weqwewe [10]3 years ago
8 0

The boxes are tied together, so their motions are equal ... displacement, velocity, and acceleration ... the same for both boxes once they get going.

The force (F) exerted on Q has to be enough to accelerate the mass of both boxes.

But the force of the string pulling box-P is only enough to move the mass of box-P with the same acceleration.

So the magnitude of the force exerted on box-P by the string (the tension in the string) is <em>less than F , (but greater than zero</em>, because it accelerates box-P).

It doesn't matter which box is heavier, lighter, more mass, or less mass.

elixir [45]3 years ago
4 0

the answer is less than F, but greater than zero


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A car (mass 1200 kg, speed 100 km/h) and a truck (mass 2800 kg, speed 50 km/h) are moving in the same direction along a highway.
Sloan [31]

Answer:

Speed of the wreck after the collision is 65 km/h

Explanation:

When a car hits truck and sticks together, the  collision would be totally inelastic.  Since the both the vehicles  locked  together, they have the same final velocity.

Mass of car  m_{1}=1200 kg

Mass of truck m_{2}=2800 kg

Initial speed of the car u_{1}=100 km /h

Initial speed  of the truck u_{2}=50 km /h

The final velocity of the wreck will be

m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}+m_{2}v_{2}

since final speed are same, v_{1}=v_{2}=v

m_{1}u_{1}+m_{2}u_{2}=(m_{1}+m_{2})v

1200\times 100 +2800 \times 50 =(1200+2800)v\\v=\frac{260000}{4000} \\v=65 km/h

5 0
2 years ago
Consider a box weight 2700 newtons resting on the ground. If the area of the box touching the ground is 1.5 square meters, what
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Answer:

The answer to your question is 1800 Pa

Explanation:

Data

Weight = 2700 N

Area = 1.5 m²

Pressure = ?

Formula

Pressure = Force / Area

The Pressure is defined as the force exerted per unit area.

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The units of pressure are Pascals (Pa)

6 0
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Answer:

The velocity of the particle from T = 0 s to T = 4 s is;

0.5 m/s

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The given parameters from the graph are;

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The graph of distance to time, from time t = 0 to time t = 4 is a straight line graph, with the velocity given by the rate of change of the displacement to the time which is dx/dt which is also the slope of the graph given as follows;

The \ slope \ of \ the \ displacement \ time \ graph, \ m =velocity, \ v= \dfrac{x_2 - x_1}{t_2 - t_1}

Therefore, \ the \ velocity \ of \ the \ particle \ v  = \dfrac{3 \  m - 1 \ m}{4 \ s - 0 \ s}  = \dfrac{2 \ m}{4 \  s} = \dfrac{1}{2} \ m/s

The velocity of the particle from t = 0 s to t  = 4 s = 1/2 m/s = 0.5 m/s.

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I need help on US history portfolio but before you help me...
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