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Natalija [7]
3 years ago
6

Two boxes, P and Q, are at rest on a frictionless horizontal surface. A light, flexible cord connects them. The mass of P is gre

ater than the mass of Q.
(As shown in the diagram,) A horizontal force of magnitude F is applied to box Q, causing both boxes to accelerate to the right.
What best describes the magnitude of the force exerted by the connecting cord on box P?

*equal to F
*greater than F
*zero
*less than F, but greater than zero
Physics
2 answers:
weqwewe [10]3 years ago
8 0

The boxes are tied together, so their motions are equal ... displacement, velocity, and acceleration ... the same for both boxes once they get going.

The force (F) exerted on Q has to be enough to accelerate the mass of both boxes.

But the force of the string pulling box-P is only enough to move the mass of box-P with the same acceleration.

So the magnitude of the force exerted on box-P by the string (the tension in the string) is <em>less than F , (but greater than zero</em>, because it accelerates box-P).

It doesn't matter which box is heavier, lighter, more mass, or less mass.

elixir [45]3 years ago
4 0

the answer is less than F, but greater than zero


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Then we have:

for cooper R=1.71 *10^-8* 1.8/(0.001628)^2= 11.61 * 10^-3Ω

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Given;

Energy of electron in ground state (n = 1 ) = 1.23 eV

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Change in energy level, = E₄ - E₁ = 0.077 eV - 1.23 eV = -1.153 eV

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For fourth excited state, n = 5

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Change in energy level, = E₅ - E₁ = 0.049 eV - 1.23 eV = -1.181 eV

The energy that must be added to the electron to move it to the fourth excited state is  -1.181 eV

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