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ioda
3 years ago
11

Conceptos básicos de la fisica

Physics
1 answer:
Andreyy893 years ago
6 0

Answer:

encontré esto fuera de google, "Estos conceptos físicos que parecen necesarios en cualquier teoría física suficientemente amplia son los llamados conceptos físicos fundamentales, una lista no exhaustiva de los mismos podría ser: espacio, tiempo, energía, masa, carga eléctrica, etc."

espero que esto ayude, que tengas un gran día, Y mantente segura! :) :D :3

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What is the horizontal component of the force on the ball after it leaves the throwers hands
e-lub [12.9K]
After the ball leaves the thrower's hand, the only force on it is
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3 years ago
A long solenoid that has 1,140 turns uniformly distributed over a length of 0.415 m produces a magnetic field of magnitude 1.00
mezya [45]

Answer:

Therefore,

Current required is , I

I = 0.0289\ Ampere

Explanation:

Given:

Turns = N = 1140

length of solenoid = l = 0.415 m

Magnetic Field,

B = 1.00\times 10^{-4}\ T

To Find:

Current , I = ?

Solution:

If N is the number of turns in the length, the total current through the rectangle is NI. Therefore, Ampere’s law applied to this path gives

\int {B} \, ds= Bl=\mu_{0}NI

Where,  

B = Strength of magnetic field

l = Length of solenoid

N = Number of turns

I = Current

\mu_{0}=Permeability\ in\ free\ space=4\pi\times 10^{-7}\ Tm/A

Therefore,

I =\dfrac{Bl}{\mu_{0}N}

Substituting the values we get

I =\dfrac{1.00\times 10^{-4}\times 0.415}{4\times 3.14\times 10^{-7}\times 1140}=0.0289\ Ampere

Therefore,

Current required is , I

I = 0.0289\ Ampere

3 0
4 years ago
A bucket of water with total mass 23 kg is attached to a rope, which in turn is wound around a 0.050-m radius cylinder at the to
Elodia [21]

As we know the relation between linear speed and angular speed as

v = R\omega

we will say

v = 8 m/s

R = 0.05 m

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\omega = 160 rad/s

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7 0
3 years ago
When resting, a person has a metabolic rate of about 3.0 105 joules per hour. The person is submerged neck-deep into a tub conta
jek_recluse [69]

Answer:

The temperature after half an hour is 19.3002^{\circ}

Solution:

As per the question;

Metabolic rate of the person is 3.0105 J/h

Temperature, T = 19.30^{\circ}

Mass of the water, m_{w} = 1.2103 kg

Time duration, t = 0.5 h = 30 min = 180 s

Now,

Heat, Q = ms\Delta t

Thus heat transfer in half an hour:

Q = 3.0105\times 0.5 = 1.505 J

Now, the temperature of water after half an hour, T' is given by:

Q = m_{w}s\Delta T = ms(T' - T)

where

s = 4186 J

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4 0
3 years ago
What is the difference between liquid water and water vapor?
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Answer:

Explanation:

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5 0
3 years ago
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