1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Tresset [83]
3 years ago
15

For an object that floats in a liquid, which of the following statements is true? Group of answer choices The specific gravity o

f the object is greater than or equal to the specific gravity of the liquid. The mass of the object is equal to the mass of liquid displaced.
Physics
1 answer:
SVEN [57.7K]3 years ago
8 0

Answer:

Explanation:

Object is Floating in a liquid

weight of object is equal to weight of displaced fluid

i.e.

\rho _oVg=\rho _mV'g

i.e.\rho _oV=mass\ of\ object

\rho _mV'=mass\ of\ liquid\ displaced

where V and V' is the volume of object and volume of object inside the liquid.

therefore mass of liquid displaced must be equal to mass of object                          

You might be interested in
Technician A says that wheel cylinder dust boots keep dust and moisture out of the cylinder bore. Technician B says that it is n
timurjin [86]

Answer:

i think its technician A

7 0
3 years ago
Decomposition breaks down organic material into simpler units and:
Lady_Fox [76]

Answer:

d.) provides proteins for plants​

Explanation:

5 0
2 years ago
Lisa is conducting an investigation to determine the coefficient of friction between two surfaces. She uses a 25 kg block. What
Paladinen [302]

Answer:

245.25

Explanation:

1 kg is 9.81 newtons

4 0
3 years ago
Read 2 more answers
A comet is in an elliptical orbit around the Sun. Its closest approach to the Sun is a distance of 4.7 1010 m (inside the orbit
Lubov Fominskaja [6]

Answer:

58515.9 m/s

Explanation:

We are given that

d_1=4.7\times 10^{10} m

v_i=9.5\times 10^4 m/s

d_2=6\times 10^{12} m

We have to find the speed (vf).

Work done by surrounding particles=W=0 Therefore, initial energy is equal to final energy.

K_i+U_i=K_f+U_f

\frac{1}{2}mv^2_i-\frac{GmM}{d_1}=\frac{1}{2}mv^2_f-\frac{GmM}{d_2}

\frac{1}{2}v^2_i-\frac{GM}{d_1}+\frac{GM}{d_2}=\frac{1}{2}v^2_f

v^2_f=2(\frac{1}{2}v^2_i-\frac{GM}{d_1}+\frac{GM}{d_2})

v_f=\sqrt{2(\frac{1}{2}v^2_i-\frac{GM}{d_1}+\frac{GM}{d_2})}

Using the formula

v_f=\sqrt{v^2_i+2GM(\frac{1}{d_2}-\frac{1}{d_1})}

v_f=\sqrt{(9.5\times 10^4)^2+2\times 6.7\times 10^{-11}\times 1.98\times 10^{30}(\frac{1}{6\times 10^{12}}-\frac{1}{4.7\times 10^{10})}

Where mass of sun=M=1.98\times 10^{30} kg

G=6.7\times 10^{-11}

v_f=58515.9 m/s

4 0
3 years ago
In the diagram, q1 = +6.39*10^_9 C and
ivanzaharov [21]

Answer:

The electric potential will be "259.695 volt".

Explanation:

In the given question, the figure is not provided. Below is the attached figure given.

Given:

q_1=6.39\times 10^{-9} \ C

q_2=3.22\times 10^{-9} \ C

AP=(0.150+0.250)

      =0.40 \ m

BP=0.25 \ m

Now,

At point P, the electric potential will be:

⇒ V=\frac{q_1}{4 \pi \epsilon_o AP } +\frac{q_2}{4 \pi \epsilon_o BP}

By putting values, we get

⇒     =9\times 10^9 [\frac{6.39\times 10^{-9}}{0.40} +\frac{3.22\times 10^{-9}}{0.25} ]

⇒     =259.695 \ Volt

4 0
3 years ago
Other questions:
  • A sample of an unknown liquid has a volume of 12.0mL and a mass of 6g. What is the density
    11·1 answer
  • A 0.50 kg rubber ball has a speed of 1.90 m/s at point a and kinetic energy of 8.9 j at point
    9·1 answer
  • Where is date that can be controlled placed on a line graph ?
    13·1 answer
  • A 300 MHz electromagnetic wave in air (medium 1) is normally incident on the planar boundary of a lossless dielectric medium wit
    15·1 answer
  • Who was the first to state the concept of an atom?
    9·2 answers
  • A wave pulse travels down a slinky. The mass of the slinky is m = 0.87 kg and is initially stretched to a length L = 6.8 m. The
    8·1 answer
  • A force of 50 N stretches a string by 4 cm,calculate the elastic constant.
    14·1 answer
  • A red balloon has a charge of -1.55μC and is held 10.5cm from a green balloon which has a charge of -1.60μC. Find the magnitude
    7·1 answer
  • Why a plastic pen which is rubbed with hair,is able to attract small pieces of papers​
    5·1 answer
  • Can some one help me with this so i can bring my grade up
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!