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alisha [4.7K]
3 years ago
10

2. What trend would you predict for the next ten years for each region

Chemistry
1 answer:
nikdorinn [45]3 years ago
6 0
The new trend will probably be the technology that's in that certain year. Like the trend in the modern days are all electronics or will have to do with electronics.

Shoutout to: @Grimmie
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One mole of an ideal gas<br><br> occupies a volume of 22.4<br><br> liters at
-Dominant- [34]

Answer : One mole of an ideal gas  occupies a volume of 22.4  liters at STP.

Explanation :

As we know that 1 mole of substance occupies 22.4 liter volume of gas at STP conditions.

STP stands for standard temperature and pressure condition.

At STP, pressure is 1 atm and temperature is 273 K.

By using STP conditions, we get the volume of 22.47 liter.

Hnece, the one mole of an ideal gas  occupies a volume of 22.4  liters at STP.

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Enzymes are proteins that speed up chemical reactions in the body. How do they work?
KATRIN_1 [288]
They work by lowering the activation energy
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6. A quiet sound exerts a pressure of 4.00 x 10^-8 kPa (kPa= kilopascals, a pressure unit). What is this pressure measured in at
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Answer:

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2 years ago
which two quantities are used to predict gravitational force according to Newton's law of universal gravitation a. mass and spee
NISA [10]

Answer:

(b). Mass and distance.

Explanation:

The gravitational force between two objects is given by Newton's law of universal gravitation. The formula is as follows :

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r is the distance between two objects

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7 0
3 years ago
The reaction 2a → a2​​​​​ was experimentally determined to be second order with a rate constant, k, equal to 0.0265 m–1min–1. if
katovenus [111]

The integrated rate law for a second-order reaction is given by:

\frac{1}{[A]t} =   \frac{1}{[A]0} + kt

where, [A]t= the concentration of A at time t,

[A]0= the concentration of A at time t=0

<span>k =</span> the rate constant for the reaction


<u>Given</u>: [A]0= 4 M, k = 0.0265 m–1min–1 and t = 180.0 min


Hence, \frac{1}{[A]t} = \frac{1}{4} + (0.0265 X 180)

<span>                                        = 4.858</span>

<span><span><span>Therefore, [A]</span>t</span>= 0.2058 M.</span>

<span>
</span>

<span>Answer: C</span>oncentration of A, after 180 min, is 0.2058 M

7 0
3 years ago
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