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Anika [276]
3 years ago
12

which two quantities are used to predict gravitational force according to Newton's law of universal gravitation a. mass and spee

d b. mass and distance c. distance and velocity d. velocity and mass
Chemistry
1 answer:
NISA [10]3 years ago
7 0

Answer:

(b). Mass and distance.

Explanation:

The gravitational force between two objects is given by Newton's law of universal gravitation. The formula is as follows :

F=G\dfrac{m_1m_2}{r^2}

Here,

G is universal gravitational constant

r is the distance between two objects

It is very clear that the gravitational force is directly proportional to the product of masses and inversely proportional to the square of the distance between them.

Hence, the two quantities are used to predict gravitational force according to Newton's law of universal gravitation are mass and distance.

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A 256 mL sample of HCl gas is in a flask where it exerts a force (pressure) of 67.5 mmHg. What is the pressure of the gas if it
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Answer:

The pressure in the new flask would be 128\; \rm mmHg if the \rm HCl here acts like an ideal gas.  

Explanation:

Assume that the \rm HCl sample here acts like an ideal gas. By Boyle's Law, the pressure P of the gas should be inversely proportional to its volume V.

For example, let the initial volume and pressure of the sample be V_1 and P_1. The new volume V_2 and pressure P_2 of this sample shall satisfy the equation: P_1 \cdot V_1 =P_2 \cdot V_2.

In this question,

  • The initial volume of the gas is V_1= 256\; \rm mL.
  • The initial pressure of the gas is P_1 = 67.5\; \rm mmHg.
  • The new volume of the gas is V_2 = 135\; \rm mL.

The goal is to find the new pressure of this gas, P_2.

Assume that this sample is indeed an ideal gas. Then the equation P_1 \cdot V_1 =P_2 \cdot V_2 should still hold. Rearrange the equation to separate the unknown, P_2. Note: make sure that the units for V_1 and V_2 are the same before evaluating. That way, the unit of

\begin{aligned} & P_2\\ &= \frac{P_1 \cdot V_1}{V_2} \\ &= \frac{256\; \rm mL \times 67.5\; \rm mmHg}{135\; \rm mL} \\ & \approx 128\; \rm mmHg\end{aligned}.

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