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Anika [276]
3 years ago
12

which two quantities are used to predict gravitational force according to Newton's law of universal gravitation a. mass and spee

d b. mass and distance c. distance and velocity d. velocity and mass
Chemistry
1 answer:
NISA [10]3 years ago
7 0

Answer:

(b). Mass and distance.

Explanation:

The gravitational force between two objects is given by Newton's law of universal gravitation. The formula is as follows :

F=G\dfrac{m_1m_2}{r^2}

Here,

G is universal gravitational constant

r is the distance between two objects

It is very clear that the gravitational force is directly proportional to the product of masses and inversely proportional to the square of the distance between them.

Hence, the two quantities are used to predict gravitational force according to Newton's law of universal gravitation are mass and distance.

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The equilibrium constant for the chemical equation N2(g)+3H2(g)↽−−⇀2NH3(g) N 2 ( g ) + 3 H 2 ( g ) ↽ − − ⇀ 2 NH 3 ( g ) is Kp =
I am Lyosha [343]

Answer:

K_c=312.13

Explanation:

The relation between Kp and Kc is given below:

K_p= K_c\times (RT)^{\Delta n}

Where,  

Kp is the pressure equilibrium constant

Kc is the molar equilibrium constant

R is gas constant

T is the temperature in Kelvins

Δn = (No. of moles of gaseous products)-(No. of moles of gaseous reactants)

For the first equilibrium reaction:

N_2_{(g)}+3H_2_{(g)}\rightleftharpoons 2NH_3_{(g)}

Given: Kp = 0.174

Temperature = 243 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T = (243 + 273.15) K = 516.15 K

R = 0.082057 L atm.mol⁻¹K⁻¹

Δn = (2)-(3+1) = -2

Thus, Kp is:

0.174= K_c\times (0.082057\times 516.15)^{-2}

K_c\frac{1}{1793.83764}=0.174

K_c=0.174\times \:1793.83764

K_c=312.13

5 0
3 years ago
Which of the following apply to unsaturated hydrocarbons? Select all that apply.
Varvara68 [4.7K]
The answer is c!!!!!!!
7 0
3 years ago
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Why do plants need sap
Vinil7 [7]
Plants don't need sap. Plants produce sap and attract bugs.
7 0
3 years ago
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The chemical formula of ordinary sugar is C12H22O11. Calculate the mass of 7.35 mol of sugar.
ch4aika [34]

First, you need to find the mass of 1 mol of sugar. Mass, or molar mass, can simply be found by adding the masses of the individual elements. These are given to you on the periodic table.

C_{12}H_{22}O_{11}

12 x 12.011 grams (molar mass of Carbon) = 144.132 g

22 x 1.008 grams (molar mass of Hydrogen) = 22.176 g

11 x 15.999 grams (molar mass of Oxygen) = 175.989 g

Add all of the pieces together.

144.132 g + 22.176 g + 175.989 g = 342.297 grams

So, if one mole has 342.297 grams, then 7.35 of that amount will be your answer.

342.297 g/mol x 7.35 mol =  2,515.88 grams

7 0
3 years ago
A gas quickly expands in an isolated environment. During the process, the gas exchanges no heat with its surroundings. The proce
AysviL [449]

Answer:

e. adiabatic process

Explanation:

Adiabatic process  -

In the thermodynamic system , an adiabatic process is the one which involves no transfer of mass or heat of the substance , is referred to adiabatic process.

In this process , the temperature need not be constant ,

But only the heat is transferred into or out of the system .

Hence, from the given information of the question,.

The correct option is e. adiabatic process .

6 0
4 years ago
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