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jekas [21]
4 years ago
15

One mole of an ideal gas occupies a volume of 22.4 liters at

Chemistry
1 answer:
-Dominant- [34]4 years ago
3 0

Answer : One mole of an ideal gas  occupies a volume of 22.4  liters at STP.

Explanation :

As we know that 1 mole of substance occupies 22.4 liter volume of gas at STP conditions.

STP stands for standard temperature and pressure condition.

At STP, pressure is 1 atm and temperature is 273 K.

By using STP conditions, we get the volume of 22.47 liter.

Hnece, the one mole of an ideal gas  occupies a volume of 22.4  liters at STP.

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Which of the following correctly identifies the number of each element involved in the chemical formulas
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D
If an element doesn’t have a number next to it that means there is only one. There a 4 hydrogens because the number is attached to the hydrogen atom. If there were 4 NH molecules the NH would be in parentheses and the 4 would be outside. Same goes for the oxygen atom and CO3 molecule.
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Which of the following is not an example of a molecule?
9966 [12]
D. F

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Read 2 more answers
Consider the following reaction:
slava [35]

Answer:

Option D is correct =  58 g

Explanation:

Data Given:

mass of LiOH = 120 g

Mass of Li3N= ?

Solution:

To solve this problem we have to look at the reaction

Reaction:

                  Li₃N (s) + 3H₂0 (l) -----------► NH₃ (g) + 3LiOH (l)

                    1 mol                                                      3 mol

Convert moles to mass

Molar mass of LiOH = 24 g/mol

Molar mass of  Li₃N = 35 g/mol

So,

                   Li₃N (s)        +     3H₂0 (l) -----------► NH₃ (g) + 3LiOH (l)

                1 mol (35 g/mol)                                                   3 mol (24 g/mol)

                   35 g                                                                         72 g

So if we look at the reaction 35 g of Li₃N react with water and produces 72 g of LiOH , then how many g of Li₃N will be react to Produce by 120 g of  LiOH

For this apply unity formula

                        35 g of  Li₃N ≅ 72 g of LiOH

                        X of  Li₃N ≅ 120 g of LiOH

By Doing cross multiplication

                  Mass of Li₃N = 35 g x 120 g / 72 g

                   mass of Li₃N =  58 g

120 g of LiOH will produce from 58 g of Li₃N

So,

Option D is correct =  58 g

5 0
3 years ago
What are the 4 different types of bonds and how are they formed?
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