One mole of an ideal gas occupies a volume of 22.4 liters at
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a. pH=2.07
b. pH=3
c. pH=8
<h3>Further explanation</h3>pH=-log [H⁺]
a) 0.1 M HF Ka = 7.2 x 10⁻⁴
HF= weak acid
b) 1 x 10⁻³ M HNO₃
HNO₃ = strong acid
c) 1 x 10⁻⁸ M HCl
Answer:
Explanation:
The relation between Kp and Kc is given below:
Where,
Kp is the pressure equilibrium constant
Kc is the molar equilibrium constant
R is gas constant
T is the temperature in Kelvins
Δn = (No. of moles of gaseous products)-(No. of moles of gaseous reactants)
For the first equilibrium reaction:
Given: Kc = 0.50
Temperature =
R = 0.082057 L atm.mol⁻¹K⁻¹
Δn = (2)-(3+1) = -2
Thus, Kp is: