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Alenkasestr [34]
4 years ago
10

1. In a single atom, no more than 2 electrons can occupy a single orbital? A. True B. False

Physics
2 answers:
Studentka2010 [4]4 years ago
4 0
1. In a single atom, no more than 2 electrons can occupy a single orbital? A. True

2. The maximum number of electrons allowed in a p sublevel of the 3rd principal level is? 
B.6

3. A neutral atom has a ground state electronic configuration of 1s^2 2s^2. Which of the following statements concerning this atom is/are correct?
B. All of the above.
ohaa [14]4 years ago
3 0

Answer:

1.True

2.6

3.All of the above

Explanation:

1.In a single atom,  no more than 2 electrons can occupy a single orbital.

By pauli exclusion principle, an orbital can contain a maximum of only 2 electrons, the two electrons must have opposite spins.

Therefore, it is true.

2.We know that maximum number of electrons in p sublevel is 6.

Hence, the maximum number of electrons allowed in a p sublevel of the 3rd principle level is 6.

3.A neutral atom has a ground state electronic configuration of 1s^2 2s^2.

Therefore, Total number of electrons=4

Atomic number=4

Number of protons=Atomic number=4

The atom has  total number of orbital is 2.

The element has no unpaired electrons.

Hence, all of the above is correct option.

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How do you calculate the refractive index of a material using the critical angle? (GCSE Physics)
Helga [31]

Answer:

µ = \frac{1}{sinC}

Explanation:

µ = 1/ sinC

µ -----> refractive index of medium

C ----> critical angle

Hope this helps!

4 0
3 years ago
A cylindrical wire made of an unknown alloy hangs from a support in the ceiling. You measure the relaxed length of the wire to b
IceJOKER [234]

Answer: hello  some of your values are wrongly written hence I will resolve your question using the right values

answer:

stiffness =  1.09 * 10^-6 N/m

Explanation:

Given data:

Length ( l ) = 16 m

radius of wire ( r ) = 3.5 m

mass ( m ) = 5kg

<u>Distance stretched (  Δl ) = 4 * 10^-3 m </u> ( right value )

<u>average bond length ( between atoms ) = 2.3 * 10^-10 m </u>( right value)

first step : calculate the area

area ( A ) = πr^2 = π * ( 3.5)^2 = 38.48 m^2

        γ          = MgL / A Δl

                    = [ (5 * 9.81 * 16 ) / ( 38.48 * (4.3*10^-3) ) ]

                    = 784.8 / 0.165 = 4756.36 N/m^2

hence : stiffness =   γ  * bond length

                           =  4756.36 * 2.3 * 10^-10  = 1.09 * 10^-6 N/m

8 0
3 years ago
Momentum data about the same objects in the same closed system is shown below.
nalin [4]

Answer:

the value of x is 3.7 because they are arranged in a particular manner.

6 0
4 years ago
Read 2 more answers
Suppose high tide is at midnight, the water level at midnight is 3 m, and the water level at low tide is 0.5 m. Assuming the nex
aev [14]

We have that the time, to the nearest minute, when the water level is at 1.125 m for the second time after midnight is

t=10.0hours

From the Question we are told that

Maximum height h_{max}=3m

Minimum height  H_{min}=0.5m

Time for  next high tide will occurT=12 hours =>720 min

Generally Average Height

h_{avg}=\frac{3+0.5}{2}\\\\h_{avg}=1.75

Therefore determine Amplitude to be

A=h_{max}=j_{avg}\\\\A=3-1.75\\\\A=1.25

Generally, the equation for Time is mathematically given by

At t=0

h(x)=Acos(Bx)+h_{avg}

Where

B=\frac{2\pi}{P}\\\\B=\frac{2\pi}{720}\\\\B=8.73*10^{-3}

Therefore

h(t)=Acos8.73*10^{-3}(t)+h_{avg}

Hence the Time at T=1.125 is

1.125(t)=1.25cos(8.73*10^{-3})(t)+1.75

-0.1249t=1.75

t=10.0hours

For more information on this visit

brainly.com/question/22361343

5 0
3 years ago
A body has a mass of 2kg.it accelerats from 20m/s to 40m/s in 4 seconds.the resultant force is<br>​
GaryK [48]

The resultant force is 8N  

Given that mass is 2kg , v= 40m/s, u =20m/s and we need to calculate resultant force
F=ma

m is given
so for a
v-u/t=a { first equation of motion }

40-20/4= 4
so a=4

F = ma =2*4 = 8N
The difference between the forces that are acting on an object as part of a system is known as the resultant force.
v = u + at is the first equation of motion. Here, v denotes the end speed, u the starting speed, an acceleration, and t the passage of time. The first equation of motion is provided by the velocity-time relation, which may be used to calculate acceleration.

To learn more about resultant force please visit -
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#SPJ1

8 0
2 years ago
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