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4 years ago

Compare lunar and solar eclipses and answer the following questions:

Physics

1 answer:

xeze [42]4 years ago

3 0

So lunar eclips earth between sun and moon
Solar eclips moon between sun and earth.
About the 3th.. im not sure, it depends on if you meen a total solar eclips or not... i think total is more rare then a lunar eclipse..

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If the mass of an object is 100 and Net force is 400, what would be the Acceleration?

ira [324]

Answer:

$4m/s^{2}$

Explanation:

I'm assuming the units for force and mass are Newtons and kilograms, respectively.

Rearranging Newton's first law (F=m*a) to solve for acceleration:

F=m*a

$a=\frac{F}{m}=\frac{400 N}{100 kg}=4m/s^{2}$

The acceleration is 4 meters per second squared and was found by rearranging Newton's first law in order to solve for acceleration.

8 0

3 years ago

Calculate the force of gravity on the 0.50-kg mass if it were 6.4×106 m above earth's surface (that is, if it were two earth rad

Sunny_sXe [5.5K]

Radius of Earth is given as

$R = 6.4 * 10^6 m$

now here the height from the surface of earth is same as that of radius

$h = 6.4 * 10^6 m$

now here the acceleration due to gravity at this height is given as

$g' = \frac{GM}{(R+h)^2}$

$g' = \frac{GM}{4R^2}$

$g' = \frac{g}{4}$

now the force of gravity on the given object will be

$F = mg'$

$F = m*\frac{g}{4}$

$F = 0.5 * \frac{9.8}{4}$

$F = 1.225 N$

<em>so the force of gravity on it is 1.225 N</em>

7 0

3 years ago

An unstable atomic nucleus of mass 1.58 10-26 kg initially at rest disintegrates into three particles. One of the particles, of

lara31 [8.8K]

Answer:

a The velocity of the third particle is $v_3 = (-15.629*10^{6}i -14.45*10^{6}j)\ m/s$

b The total kinetic energy increase $E = 6.50 *10^{-13} J$

Explanation:

To solve this question we are going to be using the concept of conservation of momentum which is mathematically represented as

$m_1v_1 +m_2v_2 +m_3v_3 = 0$

From the question

Mass of unstable atomic nucleus $m_0= 1.58 *10^{-26} kg$

Mass of x-axis particle $m_1 = 8.44* 10^{-27} kg$

Velocity of x-axis particle $v_ 1 = 4.00* 10^6 m/s$

Mass of y-axis particle $m_2 =5.20* 10^{-27} kg$

Velocity of y-axis particle $v_2 = 6.00 *10^6 m/s$

Since the initial mass is known we can obtain the mass of the third particle

Using the conservation of mass mathematical expression

$m_3 = m_0 - (m_1 +m_2)$

$m_3 = 1.58 *10^{-26} - ( 8.44* 10^{-27} + 5.20* 10^-27)$

$= 2.16 *10 ^{-27}kg$

Using the mathematical expression above for conservation of momentum

$(8.44 * 10^{-27})( 4.00* 10^6i) + (5.20 *10^{-27})(6.00* 10^6j) +(2.16*0^{-27})v_3 =0$

$v_3 = (-15.629*10^{6}i -14.45*10^{6}j)\ m/s$

The above is the vector solution now to obtain the value in numeric form we evaluate the magnitude of the vector

$Mag = \sqrt{(15.629*10^6)^2 +(14.45*10^6)^2}$

$= 21.285*10^6 \ m/s$

To obtain the total increase in kinetic energy which is mathematically represented as

$E = \frac{1}{2}m_1v_1 + \frac{1}{2}m_2v_2 + \frac{1}{2} m_3 v_3$

$E =\frac{1}{2} [(5.20*10^{-27})(6.0*0^{6})^2 + (8.44*10^{-27})(4.00*10^6)^2+\\\\(2.16*10^{-27})(21.285*10^6)^2]$

$= 6.50 *10^{-13} J$

5 0

3 years ago

Describing an organism that does not depend on another for food or a place to live

sergij07 [2.7K]

Some bacteria can live with out food or water,but even thought they don't have food nor water they still can reproduce.

4 0

4 years ago

What do we call the substances that react together (break/form chemical bonds) to form new substances?

Luda [366]

Answer: A) reactants

Explanation:

Reactants are the substances that have chemical reactions when they are combined, whereas the product is what comes from the reactants’ chemical reactions.

3 0

4 years ago

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