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sp2606 [1]
3 years ago
14

The brachialis attaches to the forearm .035 m from the elbow at an angle of 32 deg. If the brachialis produces 750 N of force, w

hat is the magnitude of the stabilizing component of the brachialis force
Physics
1 answer:
jek_recluse [69]3 years ago
4 0

Answer:

XY=636N

Explanation:

From the question we are told that:

Distance d=0.35m

Angle \theta=32\textdegree

Force F=750N

Generally the equation for magnitude of the stabilizing component of the brachialis force is mathematically given by

 XY=Fcos\theta

 XY=750cos 32\textdegree

 XY=636N

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