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3 years ago

Why is diffraction used in soil profiles?

1 answer:

7 0

Answer:X-ray diffraction (XRD) is the technique most heavily relied on in soil mineralogical analysis. X-ray diffraction is a technique that provides detailed information about the atomic structure of crystalline substances. It is a powerful tool in the identification of minerals in rocks and soils.

Explanation:

XRD is used to identify the minerals composing clay-rich, hydrothermally altered rocks that occur on several Cascade volcanoes. Such rocks are believed to play an important role in the generation of large landslides and mudflows. XRD is used to analyze saline minerals, including borates.

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In order for a color to be seen by a human, the light must be

ololo11 [35]

In the part of the spectrum our eyes can detect (a spectrum is an arry of entities, as light waves or particles, ordered in accordance with the magnitudes of a common physical property, as wavelength or mass) Hope this helps you :D

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3 years ago

Is induced current the same as induced voltage?

12345 [234]

Answer:Lenz's Law of Electromagnetic Induction. ... This voltage is called an induced emf as it has been induced into the conductor by a changing magnetic field due to electromagnetic induction with the negative sign in Faraday's law telling us the direction of the induced current (or polarity of the induced emf).

Explanation:

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3 years ago

Sound wave A delivers 2 J of energy in 2 s. Sound wave B delivers 10 J of energy in 5 s. Sound wave C delivers 2 mJ of energy in

Dmitry [639]

Answer:

In the order largest to smallest

Pc = Pb, Pa

Explanation:

Power = Energy expended/time

Pa = 2/2 = 1Watt

Pb = 10/5 = 2Watt

Pc = 2E-3/1E-3 = 2Watt

8 0

3 years ago

A 1200-kg car moving at 15.6 m/s suddenly collides with a stationary car of mass 1500 kg. if the two vehicles lock together, wha

g100num [7]

Use conservation of momentum ;

m1u1 + m2u2 = m1v1 + m2v2

1200×15.6 + 0 = 2700v

v = 18720/2700

v = 6.933 or ~ 7 m/s

5 0

3 years ago

In a track and field event, a hammer thrower accelerates the hammer (mass = 7.30 kg) from rest within four full turns (revolutio

lubasha [3.4K]

Answer:

5.69755 rad/s²

Explanation:

r = Radius = 1.3 m

v = Velocity of the hammer = 22 m/s

n = Number of revolutions = 4

Angular displacement

$\theta=n\times 2\pi\\\Rightarrow \theta=4\times 2\pi\\\Rightarrow \theta=8\pi$

$\omega_i$ = Initial angular speed = 0

Final angular speed

$\omega_f=\frac{v}{r}\\\Rightarrow \omega_f=\frac{22}{1.3}\\\Rightarrow \omega_f=16.92307\ rad/s$

Angular acceleration

$\alpha=\frac{\omega_f^2-\omega_i^2}{2\theta}\\\Rightarrow \alpha=\frac{16.92307^2-0^2}{2\times 8\pi}\\\Rightarrow \alpha=5.69755\ rad/s^2$

Angular acceleration is given by 5.69755 rad/s²

3 0

3 years ago