A plane flies horizontally at an altitude of 3 km and passes directly over a tracking telescope on the ground. when the angle of
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Answer:
F = 50636.873 N
Explanation:
given,
bucket of water = 700-kg
length of cable = 20 m
Speed = 40 m/s
angle of the cable = 38.0°
let air resistance be = F
tension in rope be = T
T cos 38° = m×g..................(1)
..........(2)
equation (1)/(2)
F = 50636.873 N
Hence the force exerted on the bucket is equal to F = 50636.873 N
Given data:
* The mass of the baseball is 0.31 kg.
* The length of the string is 0.51 m.
* The maximum tension in the string is 7.5 N.
Solution:
The centripetal force acting on the ball at the top of the loop is,
For the maximum velocity of the ball at the top of the vertical circular motion,
where g is the acceleration due to gravity,
Substituting the known values,
Thus, the maximum speed of the ball at the top of the vertical circular motion is 4.16 meters per second.