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3 years ago

How is power defined

Physics

2 answers:

Sliva [168]3 years ago

6 0

Power is the work done per second..
p=w/t

Rasek [7]3 years ago

3 0

Power is defined as the amount of work done per time taken or u can say that power is the energy over time taken.
basically p=energy /time taken

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An object 16.8 cm tall is placed in front of a converging lens. A real image, 46 cm tall, is formed on the other side of the len

worty [1.4K]

Answer:

2.74

Explanation:

Magnification = image distance/object distance

Mag = v/u

Given

v = 46cm

u = 16.8

Magnification = 46/16.8

Magnification = 2.74

Hence the magnification is 2.74

7 0

3 years ago

HURRY What happened when the speed was increased?

sp2606 [1]

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3 years ago

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A canister is filled with 310 g of ice and 100. G of liquid water, both at 0 ∘c . The canister is placed in an oven until all th

olya-2409 [2.1K]

Here in the process we require

1. Heat to melt down all ice

2. Heat to raise the temperature of whole water to 100 degree C

3. Heat to boil off the water

now here for the first part

Heat required to melt the ice

$Q_1 = mL$

$Q_1 = 310*80 = 24800 cal$

now heat required to raise the temperature to 100 degree C

$Q_2 = ms\Delta T$

$Q_2 = (310 + 100)*1*(100 - 0)$

$Q_2 = 41000 cal$

Now heat required to boil it off

$Q_3 = mL$

$Q_3 = 410*540 = 221400 cal$

now the total heat required will be

$Q = Q_1 + Q_2 + Q_3$

$Q = 24800 + 41000 + 221400$

$Q = 287200 cal$

so it required 287200 calorie heat to boil it all water

6 0

3 years ago

A tennis ball is dropped from 1.43 m above the

Rudiy27

Answer:

-5.29 m/s

Explanation:

Given:

y₀ = 1.43 m

y = 0 m

v₀ = 0 m/s

a = -9.8 m/s²

Find: v

v² = v₀² + 2a (y − y₀)

v² = (0 m/s)² + 2(-9.8 m/s²) (0 m − 1.43 m)

v = -5.29 m/s

4 0

4 years ago

A 54 kg pole vaulter running at 10 m/s vaults over the bar. Her speed when she is above the bar is 1.3 m/s. The acceleration of

Marizza181 [45]

Answer:

$h_{B} = 5.012\, m$

Explanation:

It is assumed that pole vaulter began running at a height of zero. The physical model is formed after the Principle of Energy Conservation:

$K_{A} = K_{B} + U_{B}$

$\frac{1}{2} \cdot m \cdot v_{A}^{2} = \frac{1}{2} \cdot m \cdot v_{B}^{2} + m \cdot g \cdot h_{B}$

The previous expression is simplified and required height is found:

$h_{B} = \frac{1}{2\cdot g} \cdot (v_{A}^{2}-v_{B}^{2})$

$h_{B} = \frac{1}{2 \cdot (9.807\, \frac{m}{s^{2}} )} \cdot [(10\, \frac{m}{s} )^{2}-(1.3\, \frac{m}{s} )^{2}]$

$h_{B} = 5.012\, m$

5 0

4 years ago