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lisov135 [29]
3 years ago
13

3(x + 5) = 39 I dont understand this problem

Mathematics
2 answers:
Dvinal [7]3 years ago
5 0
3(x+5)=39
3x+15=39
3x=24
x=8
ANEK [815]3 years ago
4 0
3(x+5)=39
3x+15=39
________
     -15 -15
3x=24 
/3    /3
x=8
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David, Ben, and Jordan shared stickers in a ratio of 8 : 9 : 10. If Ben had 36 stickers, how many stickers did Jordan have?
pantera1 [17]

Answer:

Jordan had 40 stickers.

Step-by-step explanation:

For this ratio, we have David:Ben:Jordan as 8:9:10, and so we need to make it as a more complex fraction, 8/9/10, now we need a multiplier to get us from 9 stickers of Jordan to 36, like a giant one. The common multiplier in this case is 4, and we know that the values must always stay proportional. We multiply everything by 4,and we get a final ratio of 32:36:40, and since Jordan is the last in the ratio David:Ben:Jordan, Jordan ends up with 40 stickers.

3 0
3 years ago
David drives 168 miles a week he fill his tank 2 times a week each fill up is 12 gallons what is gas mileage on his car
Umnica [9.8K]
I think it would be 7 miles per gallon. Just do Miles/Gallons per week.


5 0
3 years ago
Read 2 more answers
What to do ??<br> i need help please <br> asap <br> one question left
maks197457 [2]

Answer: (x^{\frac{2}{7}})(x^{\frac{3}{5}})

Step-by-step explanation:

If you took the nth root of x, it is the same as raising x to the power of 1/n. Therefore:

\sqrt[7]{x^{2} }  = (x^{2} )^{1/7} = (x^{\frac{2}{7}})\\\sqrt[5]{x^{3} }  = (x^{3} )^{1/5} = (x^{\frac{3}{5}})

And multiply:

(x^{\frac{2}{7}})(x^{\frac{3}{5}})

3 0
3 years ago
Zorba ate 75% of his carrots. He started with 24 carrots. How many carrots are left?
Stella [2.4K]

Answer:

6

Step-by-step explanation:

75% of 24=18

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5 0
3 years ago
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What is the simplified form of this expression 7(^3sqrt2x)-3(^3sqrt16x)-3(^3sqrt8x)
trasher [3.6K]

Answer:

<h2>7 \sqrt[3]{2x}  - 6 \sqrt[3]{2x}  - 6x</h2>

Solution,

7( \sqrt[3]{2x} ) - 3( \sqrt[3]{16x} ) - 3( \sqrt[3]{8x} ) \\  = 7 \sqrt[3]{2x}  - 3 \times ( \sqrt[3]{2 \times 2 \times 2 \times 2x}  - 3 \times  \sqrt[3]{2 \times 2 \times 2x}  \\  = 7 \sqrt[3]{2x}  - 3 \times (2 \sqrt[3]{2} x) - 3 \times 2x \\  = 7 \sqrt[3]{2x}  - 3 \times 2 \times  \sqrt[3]{2x}  - 3 \times 2x \\  = 7 \sqrt[3]{2x}  - 6 \sqrt[3]{2x}  - 6x

Hope this helps...

Good luck on your assignment...

7 0
3 years ago
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