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Elan Coil [88]
3 years ago
9

Epsom salts, a strong laxative used in veterinary medicine, is a hydrate, which means that a certain number of water molecules a

re included in the solid structure. The formula for Epsom salts can be written as MgSO4 · x H2O, where x indicates the number of moles of H2O per mole of MgSO4. When 3.484 g of this hydrate is heated to 250°C, all the water of hydration is lost, leaving 1.701 g of MgSO4. What is the value of x?
Chemistry
1 answer:
alexira [117]3 years ago
8 0
The values of x represents that number of moles of water molecules that is present per mole of the salt magnesium sulfate. To determine the value for this, we need to know how much is the water that is lost after heating the sample assuming that all of the water molecules are evaporated leaving only the unhydrated form of the salt. We calculate as follows:

Mass of hydrated salt = 3.484 g
Mass after heating = 1.701 g
Mass lost = 3.484 g - 1.701 g = 1.783 g

The mass lost is equal to the mass of water lost.

Moles water lost = 1.783 g ( 1 mol / 18.02 g ) = 0.0989 mol H2O
Moles of unhydrated salt = 1.701 g ( 1 mol / 120.37 g ) = 0.0141 mol MgSO4

moles water / moles MgSO4 = 0.0989 mol H2O / 0.0141 mol MgSO4 = 7

Therefore, the value of x is 7.
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Answer:

<h2>9000 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 900 × 10

We have the final answer as

<h3>9000 N</h3>

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8 0
3 years ago
PLEASE HELP AND EXPLAIN!Calculate the energy required to heat 187.0 g of ammonia from 36.1 °C to 52.9 °C. Assume the specific he
Alenkinab [10]

Answer:

E=1.48x10^4J

Explanation:

Hello!

In this case, since the energy implied in a heating process is computed by using the following equation:

E=mC(T_f-T_i)

Whereas m is the mass, C the specific heat and T the temperature. In such a way, by plugging in the given mass, specific heat and temperatures, we obtain the following energy:

E=187.0g*4.703\frac{J}{g\°C} (52.9\°C-36.1\°C)\\\\E=1.48x10^4J

Considering that the specific heat can by used by unit of °C or K because their difference is equivalent.

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3 0
3 years ago
If a mixture of a given percentage or ratio strength is diluted to twice its original quantity, its active ingredient will be co
OlgaM077 [116]

Answer:

if a mixture of a given percentage or ratio strength is diluted to twice its original quantity, its active ingredient will be contained in twice as many parts of the whole, and its strength therefore will be reduced by one-half

8 0
3 years ago
Analysis of Potassium-40 / Argon-40 determines that 37.5% of the Potassium-40 remains and 62.5% has decayed to Argon-40. What is
likoan [24]

Answer:

Option C is correct.

t = 1.95 billion years.

Explanation:

Radioactive decay follows a first order reaction kinetics.

On solving the dynamic equation (the differential equation), this is obtained

C(t) = C₀ e⁻ᵏᵗ

C(t) = amount of radioactive material remaining after time t = 37.5%

C₀ = Initial amount of radioactive material = 100%

t = time that has passed = ?

k = decay constant.

For a first order reaction, the decay constant is related to the half life through the relation

k = (In 2)/T

T = half life = 1.38 billion years

k = (In 2)/1.38

k = 0.5023 per billion years.

C(t) = C₀ e⁻ᵏᵗ

0.375 = e⁻ᵏᵗ

e⁻ᵏᵗ = 0.375

In e⁻ᵏᵗ = In 0.375 = -0.981

-kt = -0.981

t = (0.981/0.5023) = 1.95 billion years.

Hope this Helps!!!

6 0
3 years ago
Mention the oxidation state of chromium in potassium dichromate and chromium sulphate​
dedylja [7]

Answer:

Let, X be the oxidation state of Cr in K

2

Cr

2

O

7

.

2(+1)+2X+7(−2)=0

2+2X−14=0

2X=12

X=+6

Hence, the oxidation state of Cr in K

2

Cr

2

O

7

is +6.

8 0
3 years ago
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