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Elan Coil [88]
3 years ago
9

Epsom salts, a strong laxative used in veterinary medicine, is a hydrate, which means that a certain number of water molecules a

re included in the solid structure. The formula for Epsom salts can be written as MgSO4 · x H2O, where x indicates the number of moles of H2O per mole of MgSO4. When 3.484 g of this hydrate is heated to 250°C, all the water of hydration is lost, leaving 1.701 g of MgSO4. What is the value of x?
Chemistry
1 answer:
alexira [117]3 years ago
8 0
The values of x represents that number of moles of water molecules that is present per mole of the salt magnesium sulfate. To determine the value for this, we need to know how much is the water that is lost after heating the sample assuming that all of the water molecules are evaporated leaving only the unhydrated form of the salt. We calculate as follows:

Mass of hydrated salt = 3.484 g
Mass after heating = 1.701 g
Mass lost = 3.484 g - 1.701 g = 1.783 g

The mass lost is equal to the mass of water lost.

Moles water lost = 1.783 g ( 1 mol / 18.02 g ) = 0.0989 mol H2O
Moles of unhydrated salt = 1.701 g ( 1 mol / 120.37 g ) = 0.0141 mol MgSO4

moles water / moles MgSO4 = 0.0989 mol H2O / 0.0141 mol MgSO4 = 7

Therefore, the value of x is 7.
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a. t=0.553 s

b. vox(horizontal speed) = 3.62 m/s

<h3>Further explanation</h3>

Given

h = 1.5 m

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Solution

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a. h = 1/2 gt²(vertical motion=h=voyt+1/2gt²⇒voy = 0)

\tt t=\sqrt{\dfrac{2h}{g} }

t = √2h/g

t = √2.1.5/9.8

t=0.553 s

b. x=vox.t(horizontal motion)

\tt x=v_{ox}\times t

vox=x/t

vox=2/0.553

vox=3.62 m/s

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2 years ago
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labwork [276]

Answer:

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Explanation:

8 0
3 years ago
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A bottle containing 415 g of cleaning solution is used to clean hospital equipment. If the cleaning solution has a specific grav
neonofarm [45]

Answer: 483 mL of the cleaning solution are used to clean hospital equipment

Explanation:

The question requires us to calculate the volume, in mL, of solution is used to clean hospital equipment, given that 415g of this solution are used and the specific gravity of the solution is 0.860.

Measurements > Density

Specific gravity is defined as the ratio between the density of a given substance to the density of a reference material, such as water:

Specific\text{ gravity = }\frac{density\text{ of substance}}{density\text{ of reference substance}}

The density of a substance is defined as the ratio between the mass and the volume of this substance:

density=\frac{mass}{volume}

Considering the reference substance as water and its density as 1.00 g/mL, we can determine the density of the substance which specific gravity is 0.860:

0.860=\frac{density\text{ of substance}}{1.00g/mL}\rightarrow density\text{ of substance = 0.860g/mL}

Thus, taking water as the reference substance, we can say that the density of the cleaning solution is 0.860 g/mL.

Now that we know the density of the cleaning solution (0.860 g/mL) and the mass of solution that is used to clean hospital equipment (415g), we can calculate the volume of solution that is used to clean the equipment:

\begin{gathered} density=\frac{mass}{volume}\rightarrow volume=\frac{mass}{density} \\  \\ volume=\frac{415g}{0.860g/mL}=483mL \end{gathered}

Therefore, 483 mL of the cleaning solution are used to clean hospital equipment.

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