Answer:
-266 kJ
Explanation:
There is some info missing. I think this is the original question.
<em>A mixture of nitrogen and neon gas is expanded from a volume of 53.0 L to a volume of 90.0 L, while the pressure is held constant at 71.0 atm. Calculate the work done on the gas mixture. Be sure your answer has the correct sign (positive or negative) and the correct number of significant digits.</em>
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Given data
Initial volume = 53.0 L
Final volume = 90.0 L
Pressure = 71.0 atm
We can find the work (w) associated with the expansion of the gaseous mixture using the following expression.
w = - P × ΔV = - 71.0 atm × (90.0 L - 53.0 L) = -2.63 × 10³ atm . L
w = -2.63 × 10³ atm . L × (101.3 J/ 1 atm . L) = -2.66 × 10⁵ J = -266 kJ
The negative sign means that the system does work on the surroundings.
I believe the answer is letter C
Answer:
Option C. Pressure is directly proportional to the absolute temperature.
Explanation:
The ideal gas equation is given as:
PV = nRT
P = nRT/ V
Since n and V are constant, it means that P will be directly proportional to the absolute temperature
