3 years ago

What is the empirical formula of a molecule containing 18.7% lithium, 16.3% carbon, and 65% oxygen?

1 answer:

8 0

Li2CO3 ; variance= 1.26x10^-3

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Inga [223]

Answer: A) 67.1 moles

Explanation:

The balanced reaction is :

$2C(s)+O_2(g)\rightarrow 2CO(g)$

$Fe_2O_3+3CO(g)\rightarrow 2Fe+3CO_2$

To calculate the moles, we use the equation:

$\text{Number of moles of iron}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{5.00\times 1000g}{56g/mol}=89.3moles$

According to stoichiometry;

2 moles of iron is produced by 3 moles of carbon monoxide

89.3 moles of iron is produced by= $\frac{3}{2}\times 89.3=134$ moles of carbon monoxide

2 moles of carbon monoxide is produced by = 1 mole of oxygen

Thus 134 moles of carbon monoxide is produced by = $\frac{1}{2}\times 134=67.1$ moles of oxygen

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