Answer:
the spring constant k = 
the value for the damping constant 
Explanation:
From Hooke's Law
Thus; the spring constant k =
The amplitude is decreasing 37% during one period of the motion
Therefore; the value for the damping constant
Answer:
Temperature of water leaving the radiator = 160°F
Explanation:
Heat released = (ṁcΔT)
Heat released = 20000 btu/hr = 5861.42 W
ṁ = mass flowrate = density × volumetric flow rate
Volumetric flowrate = 2 gallons/min = 0.000126 m³/s; density of water = 1000 kg/m³
ṁ = 1000 × 0.000126 = 0.126 kg/s
c = specific heat capacity for water = 4200 J/kg.K
H = ṁcΔT = 5861.42
ΔT = 5861.42/(0.126 × 4200) = 11.08 K = 11.08°C
And in change in temperature terms,
10°C= 18°F
11.08°C = 11.08 × 18/10 = 20°F
ΔT = T₁ - T₂
20 = 180 - T₂
T₂ = 160°F
Hi There! :)
An equilibrium constant is not changed by a change in pressurea. True
b. False
False! :P
Answer: 15 m/s2
Explanation: I hope this helps or right because I learned this a few months ago
