Compute the work done on the table:
<em>W</em> = <em>Fd</em> = (320 N) (32 m) = 10,240 J
Divide this by the given time duration to get the power output:
<em>P</em> = <em>W</em>/∆<em>t</em> = (10,240 J) / (150 s) ≈ 63.3 W
Answer:
θ = 4.716 10⁻⁶ rad
Explanation:
In order for the releases to be considered separate, they must meet the Rayleigh criterion that establishes that the maximum diffraction of one star must coincide with the first minimum of the diffraction pattern of the second star.
We use the diffraction equation for a slit
a sin θ = m λ
The minimum occurs at m = 1
sin θ = λ / a
Since the angles in these systems are very small, we can approximate the sine to its angle in radians
θ = λ / a
The telescope has a circular aperture whereby polar cords should be used, which introduces a constant number
θ = 1.22 λ / a
Let's calculate
θ = 1.22 518 10⁻⁹ / 13.4 10⁻²
θ = 4.716 10⁻⁶ rad
The units for G must be ![[N][m^2][kg^{-2}]](https://tex.z-dn.net/?f=%5BN%5D%5Bm%5E2%5D%5Bkg%5E%7B-2%7D%5D)
Explanation:
The magnitude of the gravitational force between two objects is given by:
where
F is the force
G is the gravitational constant
are the masses of the two objects
is the separation between the objects
We know that:
- The units of F are Newtons (N)
- The units of
are kilograms (kg) - The units of are metres (m)
So, we can rewrite the equation in terms of G, to find its units:
![G=\frac{Fr^2}{m_1 m_2}=\frac{[N][m]^2}{[kg][kg]}=[N][m^2][kg^{-2}]](https://tex.z-dn.net/?f=G%3D%5Cfrac%7BFr%5E2%7D%7Bm_1%20m_2%7D%3D%5Cfrac%7B%5BN%5D%5Bm%5D%5E2%7D%7B%5Bkg%5D%5Bkg%5D%7D%3D%5BN%5D%5Bm%5E2%5D%5Bkg%5E%7B-2%7D%5D)
Learn more about gravitational force:
brainly.com/question/1724648
brainly.com/question/12785992
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The gravitational force on the car is the force popularly known
as the car's "weight". Its magnitude is
(9.8 m/s²) times (the car's mass, in kilograms) .
The unit of this quantity is [newton] .
Answer:
Explanation:
Given
Required
Determine the mass of the ball
This question will be answered using Newton's second law of motion.
Which states that
Substitute values for Force and Acceleration
Make Mass the subject
--- (approximated)
