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svlad2 [7]
3 years ago
13

Charles Darwin's groundbreaking book, The Origin of Species, described the process of

Physics
1 answer:
marshall27 [118]3 years ago
3 0
B)natural selection

Darwin discovered this idea of natural selection while on a voyage to places such as the Galapagos Islands. Essentially, the idea is that certain animals developed traits that allowed them to survive better than others.
You might be interested in
A flat coil of wire consisting of 20 turns, each with an area of 50 cm2, is positioned perpendicularly to a uniform magnetic fie
Nutka1998 [239]

Answer:

i = 0.5 A

Explanation:

As we know that magnetic flux is given as

\phi = NBA

here we know that

N = number of turns

B = magnetic field

A = area of the loop

now we know that rate of change in magnetic flux will induce EMF in the coil

so we have

EMF = NA\frac{dB}{dt}

now plug in all values to find induced EMF

EMF = (20)(50 \times 10^{-4})(\frac{6 - 2}{2})

EMF = 0.2 volts

now by ohm's law we have

current = \frac{EMF}{Resistance}

i = \frac{0.2}{0.40} = 0.5 A

5 0
3 years ago
Two magnets are placed near each other on a space station orbiting Earth.
dimulka [17.4K]

Answer: A. They will be repelled because they are in each other's magnetic

field.

Explanation: Apex and gravity and electrical don't have effect on magnets magnetic field.

5 0
3 years ago
Read 2 more answers
How much would you have to eat for your appendix to explode ? I ate so much on thanksgiving and i need to know i’m very scared
dimulka [17.4K]

Answer:

I don't think your appendix can explode because you ate too much honestly. It's not even possible to eat so much that your appendix explodes, and if you're feeling any pain it definitely isn't because your appendix is about to explode, believe me. Also you could just type it into the internet, that'd be a much faster solution.

6 0
3 years ago
A 3) How far will 20 N of force stretch a spring with a spring constant of 140 N/m?​
anyanavicka [17]

Answer:

I think the answer is

Explanation:

140N/m/20N =

7m is the answer

8 0
2 years ago
Read 2 more answers
A mass weighing 14 pounds stretches a spring 2 feet. The mass is attached to a dashpot device that offers a damping force numeri
Elodia [21]

Answer:

The motion is over-damped when λ^2 - w^2 > 0 or when b^{2} > 0.86

The motion is critically when λ^2 - w^2 = 0 or when b^{2} = 0.86

The motion is under-damped when λ^2 - w^2 < 0 or when b^{2} < 0.86

Explanation:

Using the newton second law

k is the spring constante

b positive damping constant

m mass attached

m\frac{d^{2} x}{dt^{2}} = - kx - b\frac{dx}{dt}

x(t) is the displacement from the equilibrium position

\frac{d^{2} x}{dt^{2}} +\frac{b}{m}\frac{dx}{dt} + \frac{k}{m}x = 0

Converting units of weights in units of mass (equation of motion)

m = \frac{W}{g} = \frac{14}{32} = 0.43 slug

From hook's law we can calculate the spring constant k

k = \frac{W}{s} = \frac{14}{2} = 7 lb/ft

If we put m and k into the DE, we get

\frac{d^{2} x}{dt^{2}} +\frac{b}{0.43}\frac{dx}{dt} + 16.28x = 0

Denoting the constants

2λ = \frac{b}{m} = \frac{b}{0.43}

λ = b/0.215

w^{2} = \frac{k}{m} = 16.28

λ^2 - w^2 = \frac{b^{2} }{0.046} - 16.28

This way,

The motion is over-damped when λ^2 - w^2 > 0 or when b^{2} > 0.86

The motion is critically when λ^2 - w^2 = 0 or when b^{2} = 0.86

The motion is under-damped when λ^2 - w^2 < 0 or when b^{2} < 0.86

3 0
3 years ago
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