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timurjin [86]
3 years ago
9

A family ice show is held at an enclosed arena. The skaters perform to music with level 75.0 dB. This level is too loud for your

baby, who yells at 70.0 dB (a) What total sound intensity engulfs you? W/m^2 (b) What is the combined sound level? dB
Physics
1 answer:
PolarNik [594]3 years ago
6 0

Answer:

(a). The total sound intensity 4.16\times10^{-5}.

(b). The combined sound level 76.19 dB.

Explanation:

Given that,

Sound level = 75.0 dB

We need to calculate the noise

Using formula of intensity

I=I_{0}\ 10^{\frac{\beta}{10}}

Put the value into the formula

I_{n}=10^{-12}\times10^{\dfrac{75.0}{10}}

I_{n}=0.0000316= 3.16\times10^{-5}

We need to calculate the sound intensity

I_{s}=10^{-12}\times10^{\dfrac{70.0}{10}}

I_{s}=0.00001=1.0\times10^{-5}

(a). We need to calculate the total sound intensity

The total sound intensity

I=I_{n}+I_{s}

I=3.16\times10^{-5}+1.0\times10^{-5}

I=4.16\times10^{-5}\ dB

(b). We need to calculate the combined sound level

Using formula of sound level

sound\ level =10 log(\dfrac{I}{I_{0}})

sound\ level =10 log(\dfrac{4.16\times10^{-5}}{10^{-12}})

sound\ level=76.19\ dB

Hence, (a). The total sound intensity 4.16\times10^{-5}.

(b). The combined sound level 76.19 dB.

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Voices of swimmers at a pool travel 400 m/s through the air and 1,600 m/s underwater. The wavelength changes from 2 m in the air
frosja888 [35]

The frequency of the wave has not changed.

In fact, the frequency of a wave is given by:

f=\frac{v}{\lambda}

where v is the wave's speed and \lambda is the wavelength.

Applying the formula:

- In air, the frequency of the wave is:

f=\frac{400 m/s}{2 m}=200 Hz

- underwater, the frequency of the wave is:

f=\frac{1600 m/s}{8 m}=200 Hz

So, the frequency has not changed.

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3 years ago
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A ball is thrown horizontally from the top of a building 0.10 km high. The ball strikes the ground at a point 65 m horizontally
aivan3 [116]

Answer:

option B

Explanation:

given,

height of building = 0.1 km

ball strikes horizontally to ground at = 65 m    

speed at which the ball strike = ?

vertical velocity  = 0 m/s

time at which the ball strike

s = \dfrac{1}{2}gt^2

t = \sqrt{\dfrac{2s}{g}}

t = \sqrt{\dfrac{2\times 100}{9.8}}

t = 4.53 s

vertical velocity at the time  4.53 s = g × t = 9.8 × 4.53 = 44.39 m/s

horizontal velocity = \dfrac{65}{4.53} =14.35 m/s

speed of the ball = \sqrt{44.39^2+14.35^2}

                             = 46.65 m/s

hence, the speed of the ball just before it strike the ground = 47 m/s

The correct answer is option B

5 0
3 years ago
According to the graph of displacement vs. time, what is the object's displacement at time = 60 s?
krek1111 [17]

Answer:

The straight line that is obtained, intercept it on the y-axis and the value of displacement will obtained.

Explanation:

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A transverse wave on a string is described by the wave functiony(x, t) = 0.350 sin (1.25x + 99.6t)where x and y are in meters an
ella [17]

The time interval that is between the first two instants when the element has a position of 0.175 is 0.0683.

<h3>How to solve for the time interval</h3>

We have y = 0.175

y(x, t) = 0.350 sin (1.25x + 99.6t) = 0.175

sin (1.25x + 99.6t) = 0.175

sin (1.25x + 99.6t) = 0.5

99.62 = pi/6

t1 = 5.257 x 10⁻³

99.6t = pi/6 + 2pi

= 0.0683

The time interval that is between the first two instants when the element has a position of 0.175 is 0.0683.

b. we have k = 1.25, w = 99.6t

v = w/k

99.6/1.25 = 79.68

s = vt

= 79.68 * 0.0683

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Read more on waves here

brainly.com/question/25699025

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complete question

A transverse wave on a string is described by the wave function y(x, t) = 0.350 sin (1.25x + 99.6t) where x and y are in meters and t is in seconds. Consider the element of the string at x=0. (a) What is the time interval between the first two instants when this element has a position of y= 0.175 m? (b) What distance does the wave travel during the time interval found in part (a)?

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2 years ago
A disk rotates freely on a vertical axis with an angular velocity of 50 rpm . An identical disk rotates above it in the same dir
True [87]

Answer:

Final angular velocity is 35rpm

Explanation:

Angular velocity is given by the equation:

I1w1i + I2w2i = I1w1f -I2w2f

But the two disks are identical, so Ii =I2

wf can be calculated using

wf = w1i - w2i/2

Given: w1i =50rpm w2i= 30rpm

wf= (50 + 20) / 2

wf= 70/2 = 35rpm

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