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2 years ago

Name three elements that are good conductors of electricity

Physics

2 answers:

maria [59]2 years ago

8 0

Wind, iron and ... medal..

morpeh [17]2 years ago

4 0

Silver, copper, gold, iron, mercury, and lead
are good electrical conductors.

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Which type of magnet is created from an electromagnet

lutik1710 [3]

I think the answer is c

6 0

3 years ago

A 1.3 kg ball drops vertically onto a floor, hitting with a speed of 21 m/s. It rebounds with an initial speed of 9.8 m/s. (a) W

Anarel [89]

Answer:

a) Impulse(J)=40.04 kg.m/s

b)F=2566.66 N

Explanation:

Given that

$V_1=21 m/s,V_2=9.8m/s$

We know that impulse(J) impulse is a vector quantity

$J=P_2-P_1$

We know that P=mV

So $J=m(V_2-V_1)$

Now by putting the values

J=1.3(9.8-(-21))

So impulse(J)=40.04 kg.m/s

Force is given as

$F=\dfrac{dP}{dt}$

or we can say that

$F=m\left(\dfrac{v_2-V_1}{dt}\right)$

So $F=\dfrac{40.04}{0.0156}$

F=2566.66 N

3 0

2 years ago

6. What is the GPE of a 500g box of chocolates 2 m above the ground?

Alexus [3.1K]

GPE = mgh
m = mass=500g = 0.5kg
h= height = 2m
g = gravitational field strength, 9.8 near surface of earth
therefore GPE = 0.5*9.8*2 ( 0.5*2=1 so they cancel out), GPE = 9.8J

4 0

2 years ago

How do i draw a set of three lines that has three points of intersection

Umnica [9.8K]

Assuming the lines need to be straight, I'd go with a triangle (the lines can keep going to infinity too, that's fine). But that only has 3 intersections of 2 lines, if you need all 3 lines to intersect exactly 3 times and need to be straight, it can't be done, I don't think. However, you could lay each line on top of each other to have infinite intersection points, but that's probably not what they want.

7 0

3 years ago

A refrigerator has, to transfer an average of 263 J of heat per second from temperature – 10°C to 25°C. Calculate the average po

Zolol [24]

$\huge \mathfrak \red{Answer} \\ \\ \: \: \implies \: \sf 35 \: watt \\ \\ \\ \bf \: Given \: : \\ \\ \: \: \tt Q_{1} = 263j \\ \: \tt \: T_{1} = - 10 {}^{ \circ} C \: = - 10 + 273 = 263 \: k \\ \: \tt \: T_{2} = 25^{ \circ} C = 25 + 273 = 298 \:k \\ \\ \\ \bf \: To \: Find \: : \: \: P ?\: \\ \\ \: \sf \green{Solution :} \\ \\ \: \: \large \: \bf \: P = Q _{2} - Q_{1} \\ \\ \: \: \: \tt \: \rightarrow \frac{Q_{2}}{Q_{1}} = \frac{T_{2}}{T_{1}} \\ \\ \:\rightarrow \tt \: \: \: Q_{2} = \frac{T_{2}}{T_{1}} \times Q_{1} \\ \\ \: \tt \: \: \rightarrow \: Q_{2}= \frac{298}{ \cancel 263} \times \cancel 263 \\ \\ \: \: \tt \:\rightarrow \: Q_{2} =298\: \: J / s\\ \\ \: \: \: \sf \: \bf \: \: P= Q_{2} - Q_{1} \\ \tt \: \: \: \: \: \: \: \: \: \:=298 - 263 \\ \\ \: \: \: \tt \: \: \: \: \: \: \rightarrow \: \fbox{ \blue{35 \: watt}}$

6 0

2 years ago