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Crank
4 years ago
5

Difference between Rapid and spontaneous composition​

Chemistry
1 answer:
Over [174]4 years ago
3 0

Answer:

<em><u>spontaneous composition</u></em> is the ingnition

of the substance due to the repid oxidation of its on material.

There is no requirement of heat of external sources.

<em><u>Rapid composition</u></em> on the other hand release large amount of heat and light energy.

Explosion and the firecracker is the best example of Rapid composition.

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Complete and balance the reaction in acidic solution. equation: ZnS + NO_{3}^{-} -&gt; Zn^{2+} + S + NO ZnS+NO−3⟶Zn2++S+NO Which
kotykmax [81]

Answer:

Balanced reaction: 3ZnS+2NO_{3}^{-}+8H^{+}\rightarrow 3Zn^{2+}+3S+2NO+4H_{2}O

S is oxidized and N is reduced.

NO_{3}^{-} is the oxidizing agent and ZnS is the reducing agent.

Explanation:

Reaction: ZnS+NO_{3}^{-}\rightarrow Zn^{2+}+S+NO

\Rightarrow Oxidation: ZnS\rightarrow Zn^{2+}+S

Balance charge: ZnS-2e^{-}\rightarrow Zn^{2+}+S  ...............(1)

\Rightarrow Reduction: NO_{3}^{-}\rightarrow NO

Balance H and O in acidic medium : NO_{3}^{-}+4H^{+}\rightarrow NO+2H_{2}O

Balance charge: NO_{3}^{-}+4H^{+}+3e^{-}\rightarrow NO+2H_{2}O ...............(2)

[3\timesEquation-(1)] + [ 2\timesEquation-(2)]:

3ZnS+2NO_{3}^{-}+8H^{+}\rightarrow 3Zn^{2+}+3S+2NO+4H_{2}O

Oxidation number of S increases from (-2) to (0) for the conversion of ZnS to S. Therefore S is oxidized.

Oxidation number of N decreases from (+5) to (+2) for the conversion of NO_{3}^{-} to NO. Therefore N is reduced.

NO_{3}^{-} consumes electron from ZnS. Therefore NO_{3}^{-} is the oxidizing agent and ZnS is the reducing agent.

7 0
3 years ago
What is a bond between positive and negative ion called?
amm1812

It is called a ionic bond or a electrovalent bond. Hope it helps :)

8 0
3 years ago
. A solution is prepared by dissolving 23.7 g of CaCl2 in 375 g of water. The density of the resulting solution is 1.05 g/mL. Th
mafiozo [28]

Answer:

The concentration of CaCl2 in this solution is 0.564 molar (option A)

Explanation:

Step 1: Data given

Mass of CaCl2 = 23.7 grams

Mass of water = 375 grams

Density of solution is 1.05 g/mL

Step 2: Calculate total mass

Total mass = mass of CaCl2 + mass of water

Total mass = 23.7 grams + 375 grams = 398.7 grams

Step 3: Calculate volume of the solution

Density = mass / volume

Volume = mass / density

Volume = 398.7 grams / 1.05 g/mL

Volume = 379.7 mL = 0.3797 L

Step 4: Calculate moles CaCl2

Moles CaCl2 = mass CaCl2 / molar mass CaCl2

Moles CaCl2 = 23.7 grams / 110.98 g/mol

Moles CaCl2 = 0.214 moles

Step 5: Calculate concentration

Concentration of CaCl2 = moles / volume

Concentration of CaCl2 = 0.214 moles / 0.3797 L

Concentration of CaCl2 = 0.564 mol / L = 0.564 molar

The concentration of CaCl2 in this solution is 0.564 molar (option A)

8 0
4 years ago
What is the difference between melting and dissolving
faust18 [17]
<span>In melting only one substance is involved and the liquid and solid are the same material. Heat is needed for melting to occur. Dissolving involves two materials; the resulting solution is a mixture of both. The dissolved substance is still present in the solution even though it can't be seen.</span>
7 0
3 years ago
Read 2 more answers
What is the coefficient for the oxygen molecule in the chemical equation below? 2hgo → 2hg + ? o2?
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This question is purely balancing the chemical equation where the number of atoms in reactants is equal to the number of atoms in products.
For the mentioned equation:
In the reactants, we have 2 atoms of Hg and 2 atoms of oxygen.
In the products, we should have 2 atoms of Hg and 2 atoms of oxygen.
Since the oxygen molecule is composed of 2 oxygen atoms, therefore the coefficient should be equal to 1 for the equation to be balanced.
7 0
3 years ago
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