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Crank
3 years ago
5

Difference between Rapid and spontaneous composition​

Chemistry
1 answer:
Over [174]3 years ago
3 0

Answer:

<em><u>spontaneous composition</u></em> is the ingnition

of the substance due to the repid oxidation of its on material.

There is no requirement of heat of external sources.

<em><u>Rapid composition</u></em> on the other hand release large amount of heat and light energy.

Explosion and the firecracker is the best example of Rapid composition.

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Calcutale Grxn for the following equation at 25°C: <br><br> 4KClO3(s) → 3KClO4(s) KCl(s)
Step2247 [10]

Answer:

-133.2 kJ

Explanation:

Let's consider the following balanced equation.

4 KClO₃(s) → 3 KClO₄(s) + KCl(s)

We can calculate the standard Gibbs free energy of the reaction (ΔG°rxn) using the following expression.

ΔG°rxn = 3 mol × ΔG°f(KClO₄(s)) + 1 mol × ΔG°f(KCl(s)) - 4 mol × ΔG°f(KClO₃(s))

ΔG°rxn = 3 mol × (-303.1 kJ/mol) + 1 mol × (-409.1 kJ/mol) - 4 mol × (-296.3 kJ/mol)

ΔG°rxn = -133.2 kJ

5 0
3 years ago
what kind of generalization can you make about how the number of protons and neutrons are related to each other in the elements
AURORKA [14]
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4 0
3 years ago
Draw the mechanism of polymerization of propylene with benzoyl peroxide. Show chemical structures and arrows and remember that r
allochka39001 [22]

Answer:

See explanation below

Explanation:

This mechanism of polimerization is of one type. This mechanism goes through free radical polimerization, which means that we use a initiator as the radical source, then, the polimerization begins with the breaking of the covalent bonds of that initiator. In this case the benzoyl peroxide. And this mechanism is given in three steps.

In the picture you have the mechanism in the 3 steps:

7 0
3 years ago
Consider the reaction. 2 Pb ( s ) + O 2 ( g ) ⟶ 2 PbO ( s ) An excess of oxygen reacts with 451.4 g of lead, forming 367.5 g of
Art [367]

Answer : The percent yield of the reaction is, 75.6 %

Solution : Given,

Mass of Pb = 451.4 g

Molar mass of Pb = 207 g/mole

Molar mass of PbO = 223 g/mole

First we have to calculate the moles of Pb.

\text{ Moles of }Pb=\frac{\text{ Mass of }Pb}{\text{ Molar mass of }Pb}=\frac{451.4g}{207g/mole}=2.18moles

Now we have to calculate the moles of PbO

The balanced chemical reaction is,

2Pb(s)+O_2(g)\rightarrow 2PbO(s)

From the reaction, we conclude that

As, 2 mole of Pb react to give 2 mole of PbO

So, 2.18 mole of Pb react to give 2.18 mole of PbO

Now we have to calculate the mass of PbO

\text{ Mass of }PbO=\text{ Moles of }PbO\times \text{ Molar mass of }PbO

\text{ Mass of }PbO=(2.18moles)\times (223g/mole)=486.1g

Theoretical yield of PbO = 486.1 g

Experimental yield of PbO = 367.5 g

Now we have to calculate the percent yield of the reaction.

\% \text{ yield of the reaction}=\frac{\text{ Experimental yield of }PbO}{\text{ Theoretical yield of }PbO}\times 100

\% \text{ yield of the reaction}=\frac{367.5g}{486.1g}\times 100=75.6\%

Therefore, the percent yield of the reaction is, 75.6 %

3 0
3 years ago
Place the following in order of increasing acid strength. HBrO2 HBrO3 HBrO HBrO4 A) HBrO2
jarptica [38.1K]

Answer:

HBrO4 < HBrO3 < HBrO2 < HBrO

3 0
3 years ago
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