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3 years ago

what is the difference in the charges on a balloon rubbed in your hair and a glass rod rubbed with silk? why?

1 answer:

8 0

The balloon steals electrons from your hair, leaving the hair positively charged, and the balloon negatively charged. It causes the hair to be apart from each other, because they have the same charge. Glass has a weaker hold on electrons, and silk absorbs the lost electrons.

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Rus_ich [418]

Answer:

Both are attractive as well as repulsive.

Explanation:

(Like poles repel, like charges<em> repel</em>; unlike poles attract, unlike charges <em>attract</em>).

7 0

3 years ago

How much work does this force do as the particle moves along the x-axis from x = 0 to x = l? express your answer in terms of the

nydimaria [60]

<h3><u>Answer</u>;</h3>

= F0 L ( 1 - 1/e )

<h3><u>Explanation;</u></h3>

Work done is given as the product of force and distance.

In this case;

Work done = ∫︎ F(x) dx

= F0 ∫︎ e^(-x/L) dx

= F0 [ -L e^(-x/L) ] between 0 and L

= F0 L ( 1 - 1/e )

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3 years ago

A rod of length L and electrical resistance R moves through a constant uniform magnetic field ; both the magnetic field and the

CaHeK987 [17]

Answer:

don't know what class are you you are using which mobile or laptop

6 0

3 years ago

A catapult launches a test rocket vertically upward from a well, giving the rocket an initial speed of 80.6 m/s at ground level.

galina1969 [7]

Answer:

44.64 seconds

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.8 m/s²

$v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 4.2\times 1180+80.6^2}\\\Rightarrow v=128.01\ m/s$

$v=u+at\\\Rightarrow 128.01=80.6+4.2t\\\Rightarrow t=\frac{128.01-80.6}{4.2}=11.29\ s$

<u>Time taken to reach 1180 m is 11.29 seconds</u>

$v=u+at\\\Rightarrow 0=128.01-9.8t\\\Rightarrow t=\frac{128.01}{9.8}=13.06\ s$

<u>Time the rocket will keep going up after the engines shut off is 13.06 seconds.</u>

$v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{0^2-128.01^2}{2\times -9.8}\\\Rightarrow s=836.05\ m$

The distance the rocket will keep going up after the engines shut off is 836.05 m

Total distance traveled by the rocket in the upward direction is 1180+836.05 = 2016.05 m

The rocket will fall from this height

$s=ut+\frac{1}{2}at^2\\\Rightarrow 2016.05=0t+\frac{1}{2}\times 9.8\times t^2\\\Rightarrow t=\sqrt{\frac{2016.05\times 2}{9.8}}\\\Rightarrow t=20.29\ s$

<u>Time taken by the rocket to fall from maximum height is 20.29 seconds</u>

Time the rocket will stay in the air is 11.29+13.06+20.29 = 44.64 seconds

5 0

3 years ago

Which of the following statements are TRUE about nuclear energy?

san4es73 [151]

Answer:

Explanation:

4 0

3 years ago