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mixer [17]
3 years ago
14

A solid, pure substance containing just carbon and hydrogen is found to contain 35.8g of carbon and 3.72 g of hydrogen. how many

grams of carbon will be in a 4.82 g sample of the solid?
Chemistry
1 answer:
Igoryamba3 years ago
3 0

Answer:

            4.36 g of Carbon

Solution:

Step 1: Calculate the %age of Carbon in given Solid as;

                        Mass of Carbon  =  35.8 g

                        Mass of Hydrogen  =  3.72

                        Total Mass  =  35.8 g + 3.72  =  39.52 g

                        %age of Carbon  =  (35.8 g ÷ 39.52 g) × 100

                        %age of carbon  =  90.58 %

Step 2: Calculate grams of Carbon in 4.82 g of given solid as;

                        Mass of Carbon  =  4.82 g × (90.58 ÷ 100)

                        Mass of Carbon  =  4.36 g

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Answer:-3463 kJ and -3452kJ

Explanation:

ΔU is the change in internal energy of a system and its formula is;

ΔU = q + w

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W represents the work done on or by the system. Its value is positive when work is done on the system and negative when it is done by the system.

For the system in this question, we see that it produces heat which means heat is transferred out of the system, therefore the value of q is negative, it can also be seen that work is done by the system which means that w is also negative.

Therefore,

ΔU = -q-w

ΔU = -3452 kJ – 11kJ

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ΔH = ΔU + Δ(PV)

By product rule Δ(PV) becomes ΔPV + PΔV

At constant pressure ΔP = 0. Therefore,

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ΔH = -q

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6 0
3 years ago
What is the molar Mass of 2.4g of oxygen
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Which has the highest viscory ? Milk ? Water ? Orange juice?
Snezhnost [94]
I guess you mean viscosity
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3 years ago
A 50.0 N force is applied to an object travels with a constant velocity of 20m/s, calculate
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3 years ago
White vinegar is a 5.0% by mass solution of acetic acid in water. If the density of white
Alex_Xolod [135]

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<h3>Further explanation</h3>

Given

5.0% by mass solution of acetic acid

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Required

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Solution

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\tt M=\dfrac{\%mass\times \rho\times 10}{MW~acetic~acid}\\\\M=\dfrac{5\times 1.007\times 10}{60}\\\\M=0.839

Ka for acetic acid = 1.8 x 10⁻⁵

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