3 years ago

Apply a force of 50N to the left describe the motion of the box

1 answer:

4 0

When a force is applied to the box , this will cause an acceleration to the box.
(force =mass×acceleration)

So the box has a constant acceleration and a changing velocity.

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Two airplanes leave an airport at the same time.The velocity of the first airplane is 700 m/h at a heading of 31.3 the velocity

MArishka [77]

Here in order to find out the distance between two planes after 3 hours can be calculated by the concept of relative velocity

$v_{12} = v_1 - v_2$

here

speed of first plane is 700 mi/h at 31.3 degree

$v_1 = 700 cos31.3\hat i + 700 sin31.3\hat j$

$v_1 = 598.12\hat i + 363.7\hat j$

speed of second plane is 570 mi/h at 134 degree

$v_2 = 570 cos134 \hat i + 570 sin134 \hat j$

$v_2 = -396\hat i + 410\hat j$

now the relative velocity is given as

$v_{12} = (598.12 + 396)\hat i + (363.7 - 410)\hat j$

$v_{12} =994.12\hat i -46.3 \hat j$

now the distance between them is given as

$d = v* t$

$d = (994.12 \hat i - 46.3 \hat j)* 3$

$d = 2982.36\hat i - 138.9\hat j$

so the magnitude of the distance is given as

$d = \sqrt{2982.36^2 + 138.9^2}$

$d = 2985.6$ miles

so the distance between them is 2985.6 miles

5 0

3 years ago

Read 2 more answers

Pls help will give brainliest

max2010maxim [7]

Explanation:

the correct answer is Option 5.√½gh.

hope this helps you.

5 0

2 years ago

Ava visited grand canyon. She was very impressed by the rock formations and decided to sketch them. What type of rock did Ava se

soldier1979 [14.2K]

She saw sedimentary rock

6 0

3 years ago

What is the kinetic energy of a 1500kg car with a velocity of 72.0km/h?

Sergeu [11.5K]

KE=0.5 * mass* speed^2

Convert 72 km/h to m/s by dividing it by 3.6

72/3.6= 0.277778m/s

KE=0.5*1500*0.277778
= 208.3335J
= 208J

3 0

3 years ago

Consider 2 cars traveling directly towards each other. Car A has twice the mass of Car B. In

galben [10]

Answer:

If Car A has half the mass of Car B, then it must have twice the velocity to come to a stop when colliding.

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3 years ago