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Ahat [919]
2 years ago
6

What can you conclude about the velocity of the object on the graph below

Physics
1 answer:
Mars2501 [29]2 years ago
7 0

Answer:

The more time goes on the higher in meters. So most likely more time = closer to terminal velocity. -hope this helps.

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A type O star is likely to appear _____. yellow, blue, green or red
Murljashka [212]
A type O star is likely to appear blue. 
5 0
3 years ago
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Asteroids, meteoroids, and comets are remnants of the early solar system. (T/F)
4vir4ik [10]

Answer: Asteroids, meteoroids, and comets are remnants of the early solar system. This Statement is TRUE.

Explanation:

METEOROID: these are small rocky or metallic objects found in outer space.

ASTEROIDS: these are also known as minor planets of the inner solar system. They are irregularly shaped object in space that orbits the Sun.

COMETS: these are dusty chunk of ice, that moves in a highly elliptical orbit about the sun.

Asteroids, meteoroids, and comets as remnants of the early solar system was further proved in nebular hypothesis

initially proposed in the eighteenth century by German philosopher Immanuel Kant and French mathematician Pierre-Simon Laplace. (The word nebula means a gaseous cloud.) According to the modern version of the theory, about 4.5 to 5 billion years ago the solar system developed out of a huge cloud of gases and dust floating through space. These materials were at first very thin and highly dispersed.

8 0
2 years ago
A graph of the net force F exerted on an object as a function of x position is shown for the object of mass M as it travels a ho
saul85 [17]

The change in kinetic energy is \Delta K = 3Fd

Explanation:

According to the work-energy theorem, the work done on an object is equal to the change in kinetic energy of the object. Mathematically:

W=K_f -K_i= \Delta K

where :

W is the work done on the object

K_f is the final kinetic energy of the object

K_i is the initial kinetic energy

Also, the work done on an object is (assuming that the force is applied parallel to the motion of the object):

W=F\Delta x

where

F is the magnitude of the force

\Delta x is the displacement of the object

In this problem, the force acting on the object is

F

While the displacement is the horizontal distance travelled, so

\Delta x = 3d

Therefore, the work done is

W=(F)(3d)=3Fd

And so the change in kinetic energy is

\Delta K = 3Fd

Learn more about work and kinetic energy:

brainly.com/question/6763771

brainly.com/question/6443626

brainly.com/question/6536722

#LearnwithBrainly

5 0
2 years ago
Protons in an atomic nucleus are typically 10−15 m apart. what is the electric force (in n) of repulsion between nuclear protons
dybincka [34]
<span>The electric force is given by: 
 F = [ k*(q1)*(q2) ] / d^2 
 F = Electric force 
 k = Coulomb's constant 
 q1 = Charge of one proton 
 q2 = Charge of second proton 
 d = Distance between centers of mass 
 Values: 
 F = unknown 
 k = 8.98E 9 N-m^2/C^2 
 q1 = 1.6E-19 
 q2 = 1.6E-19 
 d = 1.0E-15 m 
 Insert values into F = [ k*(q1)*(q2) ] / d^2 
 F = [ (8.98E 9 N-m^2/C^2) * (1.6E-19) * (1.6E-19) ] / (1.0E-15 m)^2 
 F = </span>229.888 N
 answer
 the electric force of repulsion between nuclear protons is 229.888 N

3 0
2 years ago
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In an experiment, a rectangular block with height h is allowed to float in two separate liquids. In the first liquid, which is w
Amiraneli [1.4K]

Answer:

The relative density of the second liquid is 7.

Explanation:

From archimede's principle we know that the force that a liquid exerts on a object equals to the weight of the liquid that the object displaces.

Let us assume that the volume of the object is 'V'

Thus for the liquid in which the block is completely submerged

The buoyant force should be equal to weight of liquid

Mathematically

F_{buoyant}=Weight\\\\\rho _{1}\times V\times g=m\times g\\\\\therefore \rho _{1}=\frac{m}{V}...............(i)

Thus for the liquid in which the block is 1/7 submerged

The buoyant force should be equal to weight of liquid

Mathematically

F'_{buoyant}=Weight\\\\\rho _{2}\times \frac{V}{7}\times g=m\times g\\\\\therefore \rho _{2}=\frac{7m}{V}.................(ii)

Comparing equation 'i' and 'ii' we see that

\rho_{2}=7\times \rho _{1}

Since the first liquid is water thus \rho _{1}=1gm/cm^3

Thus the relative density of the second liquid is 7.

6 0
3 years ago
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