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erma4kov [3.2K]
3 years ago
8

Scientists and engineers are studying ways to make artificial muscles out of carbon nanotubes. These muscles are lightweight and

can handle very high temperatures. They could be used in robots, but not in humans. What is the most likely way these muscles could lead to additional scientific progress? They could help biologists understand how human muscles work. They could allow engineers to build robots that could make cars faster. They could allow scientists to explore remote places, like other planets, in new ways. They could help chemists understand how to make new biomaterials for artificial human muscles.
Chemistry
2 answers:
wolverine [178]3 years ago
7 0

Answer:

The correct answer would be "They could allow scientists to explore remote places, like other planets, in new ways".

As the artificial muscles are lightweight and can withstand high temperatures they can be used efficiently in exploring remote places, stars, or planets where humans can not survive.

For example, they can be used to explore the inner or outer core region of the earth which would help us more in understanding the earth.

Similarly, robots with these types of muscles can be used to obtain samples from other planets which have a very high temperature such as mercury.

antoniya [11.8K]3 years ago
3 0

Answer:

C

Explanation:

got it right

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Answer:

Mass = 14.876 g

Explanation:

Given data:

Volume of gold = 0.77 cm³

Mass of gold = ?

Solution:

Density of gold from literature is 19.32 g/cm³

Formula:

d = m/v

d = density

m = mass

v = volume

by putting values,

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4 0
3 years ago
11.
Lostsunrise [7]

Answer:

(1) -12 Kcal/mol

Explanation:

Our answer options for this question are:

(1) -12 Kcal/mol

(2) -13 Kcal/mol

(3) -15 Kcal/mol

(4) -16 Kcal/mol

With this in mind, we can start with the chemical reaction (Figure 1). In this reaction, <u>two bonds are broken</u>, a C-H and a Br-Br. Additionally, a C-Br and a H-Br are <u>formed</u>.

If we want to calculate the enthalpy value, we can use the equation:

<u>ΔH=ΔHbonds broken-ΔHbonds formed</u>

If we use the energy values reported, its possible to calculate the energy for each set of bonds:

<u>ΔHbonds broken</u>

<u />

C-H = 94.5 Kcal/mol

Br-Br = 51.5 Kcal/mol

Therefore:

105 Kcal/mol + 53.5 Kcal/mol = 146 Kcal/mol

<u>ΔHbonds formed</u>

C-Br = 70.5 Kcal/mol

H-Br = 87.5 Kcal/mol

Therefore:

70.5 Kcal/mol + 87.5 Kcal/mol = 158 Kcal/mol

<u>ΔH of reaction</u>

<u />

ΔH=ΔHbonds broken-ΔHbonds formed=(146-158) Kcal/mol = -12 Kcal/mol

I hope it helps!

<u />

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