Question

Calculate the frequency required to eject electrons from gold with a work function of 8.76 x 10-19 J

Answer 1

$hf=W+\frac{mv^{2}}{2}\\\\ f=\frac{W+\frac{mv^{2}}{2}}{h}\\\\\ W=8,76*10^{-19}J\\ m=9,11*10^{-31}kg\\ v=3*10^{8}\frac{m}{s}\\ h=6,63*10^{-34}Js\\\\\\ f=\frac{8,76*10^{-19}J+\frac{9,11*10^{-31}kg*(3*10^{8}\frac{m}{s})^{2}}{2}}{6,63*10^{-34}Js}=7,5*10^{19}Hz$