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BartSMP [9]
3 years ago
8

Calculate the frequency required to eject electrons from gold with a work function of 8.76 x 10-19 J

Chemistry
1 answer:
Savatey [412]3 years ago
5 0
hf=W+\frac{mv^{2}}{2}\\\\
f=\frac{W+\frac{mv^{2}}{2}}{h}\\\\\

W=8,76*10^{-19}J\\
m=9,11*10^{-31}kg\\
v=3*10^{8}\frac{m}{s}\\
h=6,63*10^{-34}Js\\\\\\
f=\frac{8,76*10^{-19}J+\frac{9,11*10^{-31}kg*(3*10^{8}\frac{m}{s})^{2}}{2}}{6,63*10^{-34}Js}=7,5*10^{19}Hz
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What is one of the BEST practices officers should use when securing a crime scene?
notsponge [240]

Answer:

The best practices officers should use when securing a crime scene is option D

D. They should secure a larger area than the actual crime scene

Explanation:

Officers should secure the scene by limiting access to the scene and movement within the scene

Three layers of secure perimeter should be used by officers to secure a crime scene, with the smallest inside perimeter being the actual crime scene

Next to the crime scene, is an inner perimeter which is the designated meeting point/command post

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7 0
2 years ago
Ammonia can be produced in the laboratory by heating ammonium chloride
AnnyKZ [126]

Answer:

Mass = 2.89 g

Explanation:

Given data:

Mass of NH₄Cl = 8.939 g

Mass of Ca(OH)₂ = 7.48 g

Mass of ammonia produced = ?

Solution:

2NH₄Cl   +  Ca(OH)₂     →    CaCl₂ + 2NH₃ + 2H₂O

Number of moles of NH₄Cl:

Number of moles = mass/molar mass

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Number of moles = 0.17 mol

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Number of moles = 0.10 mol

Now we will compare the moles of ammonia with both reactant.

                      NH₄Cl          :          NH₃

                          2              :           2

                         0.17          :          0.17

                   Ca(OH)₂         :          NH₃

                        1                :           2

                    0.10              :          2/1×0.10 = 0.2 mol

Less number of moles of ammonia are produced by ammonium chloride it will act as limiting reactant.

Mass of ammonia:

Mass = number of moles × molar mass

Mass = 0.17 mol × 17 g/mol

Mass = 2.89 g

6 0
2 years ago
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