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2 years ago

Boron occurs naturally as two isotopes. What is the difference between these isotopes?

Chemistry

1 answer:

Murrr4er [49]2 years ago

8 0

Answer:

Number of neutrons and stability

Explanation:

An isotope of an element is basically the same element but with different number of neutrons. For example here, boron can exist in the forms of boron-10 and boron-11, and so the latter would have one more neutron than the former one.

Adding an extra neutron may or may not disrupt the strong force that much, and so the half-life and stability of the new isotope can be slightly different than its most stable one.

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There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. In

Scorpion4ik [409]

Answer:

The net change in enthalpy for the formation of one mole of acrylic acid from calcium carbide, water and carbon dioxide is -470.4 kJ/mol.

Explanation:

Step 1 : Calcium carbide and water react to form acetylene and calcium hydroxide

$CaC_2(s)+2H_2O(g)\rightarrow$

$C_2H_2(g)+Ca(OH)_2(s),\Delta H_1=-414 kJ$ ..[1]

Step 2 : Acetylene, carbon dioxide and water react to form acrylic acid

$6C_2H_2(g)+3CO_2(g)+4H_2O(g)\rightarrow 5CH_2CHCOOH(g),\Delta H_2=132 kJ$ ..[2]

Using Hess's law:

[1] × 6 + [2]

$6CaC_2(s)+16H_2O(g)+3CO_2\rightarrow 5CH_2CHCOOH(g)+6Ca(OH)_2(s),\Delta H_3=?$

$\Delta H_3=6\times \Delta H_1+\Delta H_2$

$\Delta H_3=6\times (-414 kJ)+132 kJ=-2352 kJ$

The energy released on formation of 5 moles of acrylic acid = -2352 kJ

The energy released on formation of 1 moles of acrylic acid :

$=\frac{-2352 kJ}{5 mol}=-470.4 kJ/mol$

Hence, the net change in enthalpy for the formation of one mole of acrylic acid from calcium carbide, water and carbon dioxide is -470.4 kJ/mol.

5 0

3 years ago

How many grams of 02 will be formed from 6.5 moles of KCLO3

Allisa [31]

Answer:

312 g of O₂

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2KClO₃ —> 2KCl + 3O₂

From the balanced equation above,

2 mole of KClO₃ decomposed to 3 moles of O₂.

Next, we shall determine the number of mole of O₂ produced by the reaction of 6.5 moles of KClO₃. This can be obtained as follow:

From the balanced equation above,

2 mole of KClO₃ decomposed to 3 moles of O₂.

Therefore, 6.5 moles of KClO₃ will decompose to produce = (6.5 × 3)/2 = 9.75 moles of O₂.

Finally, we shall determine the mass of 9.75 moles of O₂. This can be obtained as follow:

Mole of O₂ = 9.75 moles

Molar mass of O₂ = 2 × 16 = 32 g/mol

Mass of O₂ =?

Mole = mass / Molar mass

9.75 = Mass of O₂ / 32

Cross multiply

Mass of O₂ = 9.75 × 32

Mass of O₂ = 312 g

Thus, 312 g of O₂ were obtained from the reaction.

4 0

2 years ago

Read 2 more answers

How many atoms are in .47 moles of argon

lesantik [10]

Answer:

$\large \boxed {2.8 \times 10^{23}\text{ atoms Ar}}$

Explanation:

$\text{Atoms of Ar} = \text{0.47 mol Ar} \times \dfrac{ 6.022 \times 10^{23}\text{ atoms Ar}}{\text{1 mol Ar}}\\\\= \large \boxed {\mathbf{2.8 \times 10^{23}}\textbf{ atoms Ar}}$

3 0

3 years ago

If 7.0 mol sample of a gas has a volume of 12.2 L, what would the volume be if the amount of gas was increased to 16.8 mol

Leviafan [203]

Answer:

$V_{2} = 29.28\,L$

Explanation:

Let assume that gas behaves ideally and experiments an isobaric and isothermal processes. The following relationship is applied to determined the final volume:

$\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}$

$V_{2} = V_{1} \cdot \left(\frac{n_{2}}{n_{1}} \right)$

$V_{2} = (12.2\,L)\cdot \left(\frac{16.8\,moles}{7\,moles} \right)$

$V_{2} = 29.28\,L$

5 0

3 years ago

Electrolysis is used in the electroplating of metals. The same amount of current is passed through separate aqueous solutions of

Aleonysh [2.5K]

Answer:

CuSO4 cell will have the greatest amount of deposit among all three. The deposit will occur at the cathode

Explanation:

The valence of the elements in this case is as follows -

Cu - 2e-

Sn - 4e-

Cr - 3e-

CuSO4 cell will have the greatest amount of deposit among all three

The atoms of copper metal will deposit at the cathode. At the cathode, the least number of moles of electrons needed .

Hence, more amount of copper can be extracted out by the electrolyte

3 0

3 years ago