Answer: True
Explanation: Specific Gravity of a body, also called its Relative Density, is the ratio of the density of that body to the density of a reference material (usually water).
With the Mathematics done right, it is evident that the specific gravity of a body would be equal to the ratio of mass/weight of the body to the mass/weight of an equal volume of water.
S.G = (Density of body)/(Density of water)
Density of Body = (mass/weight of body)/(volume of body)
Density of water = (mass/weight of water)/(volume of water)
If volume of Body = Volume of water, then,
S.G = (Mass/Weight of body)/(Mass/Weight of equal volume of water)
Proved!!
Answer:
2.12atm
Explanation:
Boyle's Law: P1V1 = P2V2
Manipulate to solve for unknown: P2 = P1V1/V2
Substitute values: P2=(1.2atm)(4.6L)/2.6L
P2 = 2.1230769atm
Round to 3 sig figs to get 2.12atm
Answer: Yes, 
is a strong acid.
acid = , conjugate base = 
, base = 
, conjugate acid = 
Explanation:
According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.
Yes is a strong acid as it completely dissociates in water to give 
ions.
For the given chemical equation:
Here, is loosing a proton, thus it is considered as an acid and after losing a proton, it forms which is a conjugate base.
And, is gaining a proton, thus it is considered as a base and after gaining a proton, it forms which is a conjugate acid.
Thus acid =
conjugate base =
base =
conjugate acid = .
The term that best described a 10 gram of KClO3 per 100 grams of water solution at 30 degree Celcius is Saturated. The solubility chart is needed for this work. If the solubility chart is drawn for KClO3, it will be observed that the proportion of KClO3 that is needed to dissolve in 100ml of water to make the solution saturated is 10 grams at 30 degree Celcius.
