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3 years ago

13

Is gravity keeps the planets in orbit around the sun a. True b. False

1 answer:

salantis [7]3 years ago

3 0

True. It's a bit more complex than simply that, but for the question you asked the answer is A.
Inertia also works in tandem with gravity, and plants orbit they don't revolve (kudos on that! Small pet peeve of mine). Newtons laws of physics will help you understand this more; remember to keep in mind we are talking about space so the suns mass has gravitational pull, but space has no gravity- So inertia plays an important part as well.

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Why is it important to have a balanced centrifuge?

ratelena [41]

It is important to properly balance a centrifuge because an unbalanced machine can damage the rotor, cause catastrophic damage to the machine itself, or even injure or kill lab personnel working in the room. Balancing a centrifuge involves spreading the weight of the samples across the entire rotor.

8 0

4 years ago

A couple of astronauts agree to rendezvous in space after hours. Their plan is to let gravity bring them together. She has a mas

Oduvanchick [21]

Answer:

(a) Acceleration of female astronaut = 9.33*10^-12 m/s^2; Acceleration of male astronaut = 7.56*10^-12 m/s^2

(b) 27.013 days

(c) No, their accelerations would not be constant.

Explanation:

In the given question, we have:

Mass of female astronaut $M_{1}$ = 60.0 kg

Mass of male astronaut $M_{2}$ = 74.0 kg

Distance between them (S) = 23.0 m

(a) The free-body diagram is shown in the attached figure.

Using the equations below, the initial accelerations of the two astronauts can be calculated:

Force of gravity (F) = $\frac{G*M_{1}*M_{2}}{S^{2} }$

G = 6.67*10^-11 $\frac{m^{3} }{kg*s^{2} }$

F = (6.67*10^-11 *60*74)/23^2 = 5.598*10^-10 N

For the female astronaut, her initial acceleration = F/ $M_{1}$ = 5.598*10^-10/60 = 9.33*10^-12 m/s^2

For the male astronaut, his acceleration = F/ $M_{2}$ = 5.598*10^-10/74 = 7.56*10^-12 m/s^2

(b) Since the different between their mass is not much, we can deduce that:

$a_{average} = \frac{a_{1}+a_{2}}{2}$ = (9.33*10^-12 + 7.56*10^-12)/2 = 8.445*10^-12 m/s^2

Using the equation below, we can calculate the the time:

S = ut + 1/2 (at^2) where u = 0

23 = 1/2 (8.445*10^-12)*t^2

t^2 = 5.447*10^12

t = 2333883.044 s = 27.013 days

(c) No, their accelerations will not be constant. It will increase because their radii would be decreasing.

8 0

3 years ago

A nonmechanical water meter could utilize the Hall effect by applying a magnetic field across a metal pipe and measuring the Hal

Serga [27]

Answer:

The velocity is $v =2.455 \ m/s$

Explanation:

From the question we are told that

The diameter of the pipe is $d = 4.25 \ cm = 0.0425 \ m$

The magnetic field is $B = 0.575 \ T$

The hall voltage is $V_H = 60.0 mV = 60 *10^{-3} \ V$

Generally the average fluid velocity is mathematically represented as

$v = \frac{V}{ B * d }$

=> $v = \frac{60*10^{-3}}{ 0.575 * 0.0425 }$

=> $v =2.455 \ m/s$

5 0

3 years ago

What is the number of daylight hours of daylight difference in the summer for two regions located at different latitudes in the

ruslelena [56]

To be completely honest the answer is 74

4 0

3 years ago

A 800 J <br> B -800 J <br> C 400 J <br> D -400 J <br> ??

Ierofanga [76]

I think it will be 800j because right absorb mean getting more

8 0

4 years ago