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charle [14.2K]
3 years ago
15

A velocity selector in a mass spectrometer uses a 0.100-T magnetic field. (a) What electric field strength is needed to select a

speed of 4.00 . 106 m/s
Physics
1 answer:
Wewaii [24]3 years ago
6 0

Answer:

The electric field strength needed is 4 x 10⁵ N/C

Explanation:

Given;

magnitude of magnetic field, B = 0.1 T

velocity of the charge, v = 4 x 10⁶ m/s

The velocity of the charge when there is a balance in the magnetic and electric force is given by;

v = \frac{E}{B}

where;

v is the velocity of the charge

E is the electric field strength

B is the magnetic field strength

The electric field strength needed is calculated as;

E = vB

E = 4 x 10⁶ x 0.1

E = 4 x 10⁵ N/C

Therefore, the electric field strength needed is 4 x 10⁵ N/C

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The change in potential along a path from C to D due to a small charged sphere is 900 V.

Given:

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We know that the electric potential is given as:

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The electric potential at point C due to charged sphere can be given as:

V₁ = k Q/r₁

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ΔV = V₂ - V₁

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Learn more about the electric potential here:

<u>brainly.com/question/12645463</u>

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Answer:

Density of 127 I = \rm 1.79\times 10^{14}\ g/cm^3.

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Explanation:

Given, the radius of a nucleus is given as

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The density of the nucleus is defined as the mass of the nucleus M per unit volume V.

\rm \rho = \dfrac{M}{V}=\dfrac{M}{\dfrac 43 \pi r^3}=\dfrac{M}{\dfrac 43 \pi (kA^{1/3})^3}=\dfrac{M}{\dfrac 43 \pi k^3A}.

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