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2 years ago

Object a travels in the +x-direction before hitting a stationary object

2 answers:

8 0

The object’s resultant angle of motion with the +x-axis after the collision is 47°

<span>From object A:

1) x-momentum is 5.7 × 10^4 kilogram meters/second,
2) y-momentum is 6.2 × 10^4 kilogram meters/second.

Now, we know, tan</span>Ф = $\frac{y}{x}$

⇒tanФ = $\frac{6.2 × 10^4 }{5.7 × 10^4}$

⇒tanФ = 1.088

⇒ Ф = $tan^{-1}$ 1.088
= 47.4 ≈ 47

barxatty [35]2 years ago

8 0

Answer: C

Explanation:

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Range of motion is the distance an object can travel when separated from another object. Please select the best answer from the

Lady_Fox [76]

Based on the given statement above, the correct answer would be FALSE. It is not true that range of motion is the distance an object can travel when separated from another object because range of motion or ROM is the distance--linear or angular--<span>that a movable object may normally travel while properly ATTACHED (not separated) to another. Hope this answer helps.</span>

7 0

2 years ago

Ryan is driving home from work and notices a deer leaping onto the road about 25 m in front of his car. He immediately applies t

Anvisha [2.4K]

Answer:

mu = 0.56

Explanation:

The friction force is calculated by taking into account the deceleration of the car in 25m. This can be calculated by using the following formula:

$v^2=v_0^2+2ax\\$

v: final speed = 0m/s (the car stops)

v_o: initial speed in the interval of interest = 60km/h

= 60(1000m)/(3600s) = 16.66m/s

x: distance = 25m

BY doing a the subject of the formula and replace the values of v, v_o and x you obtain:

$a=\frac{v^2-v_o^2}{2x}=\frac{0m^2/s^2-(16.66m/s)^2}{2(25m)}=-5.55\frac{m}{s^2}$

with this value of a you calculate the friction force that makes this deceleration over the car. By using the Newton second's Law you obtain:

$F_f=ma=(1490kg)(5.55m/s^2)=8271.15N$

Furthermore, you use the relation between the friction force and the friction coefficient:

$F_f= \mu N=\mu mg\\\\\mu=\frac{F_f}{mg}=\frac{8271.15N}{(1490kg)(9.8m/s^2)}=0.56$

hence, the friction coefficient is 0.56

6 0

2 years ago

if two point charges are separated by 1.5 cm and have charge values of 2.0 and -4.0, respectively, what is the value of the mutu

RUDIKE [14]

Complete question:

if two point charges are separated by 1.5 cm and have charge values of +2.0 and -4.0 μC, respectively, what is the value of the mutual force between them.

Answer:

The mutual force between the two point charges is 319.64 N

Explanation:

Given;

distance between the two point charges, r = 1.5 cm = 1.5 x 10⁻² m

value of the charges, q₁ and q₂ = 2 μC and - μ4 C

Apply Coulomb's law;

$F = \frac{k|q_1||q_2|}{r^2}$

where;

F is the force of attraction between the two charges

|q₁| and |q₂| are the magnitude of the two charges

r is the distance between the two charges

k is Coulomb's constant = 8.99 x 10⁹ Nm²/C²

$F = \frac{k|q_1||q_2|}{r^2} \\\\F = \frac{8.99*10^9 *4*10^{-6}*2*10^{-6}}{(1.5*10^{-2})^2} \\\\F = 319.64 \ N$

Therefore, the mutual force between the two point charges is 319.64 N

4 0

3 years ago

100pt need help asap Give a real-world example of an energy transformation that uses two of the following forms of energy: chemi

vazorg [7]

I'm trying to think of something that will give you the biggest bang for your buck, meaning what would give you the most number of energy transformations in their use.

Wind energy uses those great big windmills that transform wind into electrical energy. The wind is caused by the sun (which has nuclear energy, light energy and the earth's rotation which is not related to the sun but is mechanical energy). To start with you use mechanical energy. That energy drives a generator that stores it's energy in a battery. You have changed electrical energy into chemical energy. The batteries, on a calm day take over and provide electrical energy that must be transported to the consumers using it. Proponents of wind energy say that it is pollution free. It's not exactly true. The batteries used have to be manufactured (not a clean industry) and when they wear out, they pollute the environment if they cannot be recharged with new battery plates and acid (chemical).

Added to which wind energy is very noisy (sound energy) which has been linked to serious diseases.

6 0

3 years ago

Read 2 more answers

Suppose that you take a 10 kg mass on the surface of the earth and then place it on the moon. What will

sergey [27]

Answer:

10 kg

Explanation:

The mass of an object does not change even if the amount of gravtiy changes.

5 0

2 years ago