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3 years ago

Object a travels in the +x-direction before hitting a stationary object

2 answers:

8 0

The object’s resultant angle of motion with the +x-axis after the collision is 47°

<span>From object A:

1) x-momentum is 5.7 × 10^4 kilogram meters/second,
2) y-momentum is 6.2 × 10^4 kilogram meters/second.

Now, we know, tan</span>Ф = $\frac{y}{x}$

⇒tanФ = $\frac{6.2 × 10^4 }{5.7 × 10^4}$

⇒tanФ = 1.088

⇒ Ф = $tan^{-1}$ 1.088
= 47.4 ≈ 47

barxatty [35]3 years ago

8 0

Answer: C

Explanation:

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3 years ago

Some element can be either solid or liquid. At the melting point, the liquid has 8 × 10-22 J more enthalpy per atom than the sol

OlgaM077 [116]

Answer:

481.76 J/mol

133.33 K

Explanation:

$N_A$ = Avogadro's number = $6.022\times 10^{23}$

Change in enthalpy is given by

$\Delta H=8\times 10^{-22}\times 6.022\times 10^{23}\\\Rightarrow \Delta H=481.76\ J/mol$

Entropy is given by

$\Delta S=6\times 10^{-24}\times 6.022\times 10^{23}\\\Rightarrow \Delta S=3.6132\ J/mol K$

Latent heat of fusion is given by

$L_f=\Delta H\\\Rightarrow L_f=481.76\ J/mol$

The latent heat of fusion is 481.76 J/mol

Melting point is given by

$T_m=\dfrac{L_f}{\Delta S}\\\Rightarrow T_m=\dfrac{8\times 10^{-22}\times 6.022\times 10^{23}}{6\times 10^{-24}\times 6.022\times 10^{23}}\\\Rightarrow T_f=133.33\ K$

Melting occurs at 133.33 K

3 0

3 years ago

If the earth's magnetic field has strength 0.50 gauss and makes an angle of 20.0 degrees with the garage floor, calculate the ch

lys-0071 [83]

Answer:

ΔΦ = -3.39*10^-6

Explanation:

Given:-

- The given magnetic field strength B = 0.50 gauss

- The angle between earth magnetic field and garage floor ∅ = 20 °

- The loop is rotated by 90 degree.

- The radius of the coil r = 19 cm

Find:

calculate the change in the magnetic flux δφb, in wb, through one of the loops of the coil during the rotation.

Solution:

- The change on flux ΔΦ occurs due to change in angle θ of earth's magnetic field B and the normal to circular coil.

- The strength of magnetic field B and the are of the loop A remains constant. So we have:

Φ = B*A*cos(θ)

ΔΦ = B*A*( cos(θ_1) - cos(θ_2) )

- The initial angle θ_1 between the normal to the coil and B was:

θ_1 = 90° - ∅

θ_1 = 90° - 20° = 70°

The angle θ_2 after rotation between the normal to the coil and B was:

θ_2 = ∅

θ_2 = 20°

- Hence, the change in flux can be calculated:

ΔΦ = 0.5*10^-4*π*0.19*( cos(70) - cos(20) )

ΔΦ = -3.39*10^-6

8 0

3 years ago

A school bus travels 50 km/hr for 0.75 hr. How far did the bus go?

PSYCHO15rus [73]

Explanation:

speed = 50 km/h

time = 0.75 hr

dist. = time × speed

dist. = 0.75 × 50

dist.= 37.5 km

7 0

3 years ago

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