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4 years ago

The diagram shows light passing through and opening and forming bonds. Which two order bands are the dimmest?

Physics

2 answers:

myrzilka [38]4 years ago

8 0

The correct answer is (D) because I said it is lol, but fr i'm right!

Oxana [17]4 years ago

7 0

I think its option d
n=2 n=3

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In one of the classic nuclear physics experiments at the beginning of the 20th century, alpha particles were accelerated toward

Murljashka [212]

Answer:

Explanation:

In the whole process , electric potential energy is converted into kinetic energy .

Kinetic energy = 3.83 MeV

= 3.83 x 1.6 x 10⁻¹⁶ J

= 6.128 x 10⁻¹⁶ J .

Let the closest distance of approach be r .

Electric potential energy = k Q q / r , Q is charge on nucleus , q is charge on alpha particle , r is closest distance .

Electric potential energy = 9 x 10⁹ x 79 x 1.6 x 10⁻¹⁹ x 2 x 1.6 x 10⁻¹⁹ / r

= 3640.32 x 10⁻²⁹ / r

So,

6.128 x 10⁻¹⁶= 3640.32 x 10⁻²⁹ / r

r = 3640.32 x 10⁻²⁹ / 6.128 x 10⁻¹⁶

= 594.05 x 10⁻¹³

= 59.405 x 10⁻¹²

= 59.405 pm .

6 0

3 years ago

Need help with this science!!

noname [10]

Lol, I remember I helped my sister with this question but anyways, the card flew because of inertia and the quarter fell in the glass because of gravity :).

3 0

3 years ago

A NASA satellite has just observed an asteroid that is on a collision course with the Earth. The asteroid has an estimated mass,

Citrus2011 [14]

Answer:

v = 7934.2 m/s

Explanation:

Here the total energy of the Asteroid and the Earth system will remains conserved

So we will have

$-\frac{GMm}{r} + \frac{1}{2}mv_0^2 = -\frac{GMm}{R} + \frac{1}{2}mv^2$

now we know that

$v_0 = 660 m/s$

$M = 5.98 \times 10^{24} kg$

$m = 5 \times 10^9 kg$

$r = 4 \times 10^9 m$

$R = 6.37 \times 10^6 m$

now from above formula

$GMm(\frac{1}{R} - \frac{1}{r}) + \frac{1}{2}mv_0^2 = \frac{1}{2}mv^2$

now we have

$2GM(\frac{1}{R} - \frac{1}{r}) + v_0^2 = v^2$

now plug in all data

$2(6.67 \times 10^{-11})(5.98 \times 10^{24})(\frac{1}{6.37 \times 10^6} - \frac{1}{4 \times 10^9}) + (660)^2 = v^2$

$v = 7934.2 m/s$

5 0

3 years ago

How many full length strands of hair are collected from the scalp to use as a sample?

laila [671]

50 strands is the standard procedure

4 0

3 years ago

Write an expression for a harmonic wave with an amplitude of 0.19 m, a wavelength of 2.6 m, and a period of 1.2 s. The wave is t

zlopas [31]

Answer:

$y = 0.19 sin(5.23 t - 2.42x + \frac{\pi}{2})$

Explanation:

As we know that the wave equation is given as

$y = A sin(\omega t - k x + \phi_0)$

now we have

$A = 0.19 m$

$\lambda = 2.6 m$

so we have

$k = \frac{2\pi}{\lambda}$

$k = \frac{2\pi}{2.6}$

$k = 2.42 per m$

also we have

$T = 1.2 s$

so we have

$\omega = \frac{2\pi}{T}$

$\omega = \frac{2\pi}{1.2}$

$\omega = 5.23 rad/s$

now we know that at t = 0 and x = 0 wave is at y = 0.19 m

so we have

$\phi_0 = \frac{\pi}{2}$

so we have

$y = 0.19 sin(5.23 t - 2.42x + \frac{\pi}{2})$

6 0

3 years ago