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uranmaximum [27]
3 years ago
9

When two or more capacitors are connected in series across a potential difference:

Physics
1 answer:
34kurt3 years ago
7 0

Answer:

A) and B) are correct.

Explanation:

Let's take a look at the attached picture. Now

The total voltage across both capacitors is the same as the sum of the voltage from each device, that statement is true for any electrical device connected in series. So a) is TRUE

The equivalent capacitance is going to be: \frac{1}{C_{total}}=\frac{1}{C_1} +\frac{1}{C_2}

And that value can be mathematically proven that is always less than any of the values of each capacitor. So b is TRUE

And through both capacitors flow the same current, but the amount of charge depends on the value of the capacitors, so only could be the same if the capacitors are the same value. Otherwise, don't. C) not always, so FALSE

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A car drives 200 miles east then makes a turn and travels 50 miles north before
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Answer:

Total distance= 250miles

Displacement= 206.15 miles

Explanation:

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Solar winds have an influence all the way to about 160 AU from the Sun. About how many kilometers is that? 24,000,000,000 km 48,
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Please help on this question​
Yanka [14]

TLDR: R=30 Ohms, I=2 Amps, 12V, 28V, 20V, respectively.

Alright, let’s break this down. There are three resistors in this circuit, meaning that we have to find the equivalent resistance. Luckily, they are all in parallel with one another; this means we can add the resistances together without having to do inverses like in a series problem. This means that the equivalent resistance, Req, would equal:

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Req=6 + 14+ 10

Req=30 Ohms

This means that we could theoretically replace all three resistors with a 30 Ohm resistor and accomplish the same goal. Now, the entire voltage of the system would normally be reduced to zero after passing through the resistors - in this case, the 60 Vs would be lost after passing through 30 Ohms. This means we’re losing 2V/Ohm; now we can figure out how much we’re losing at each resistor.

By losing 2V per Ohm, we’re losing 12 V at the first resistor, 28 V at the second resistor, and 20 V at the third resistor.

Finally, we can calculate the current through the circuit; for a series circuit, the current remains the same. Using V=IR, we can find that:

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Hope this helps!

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