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uranmaximum [27]
3 years ago
9

When two or more capacitors are connected in series across a potential difference:

Physics
1 answer:
34kurt3 years ago
7 0

Answer:

A) and B) are correct.

Explanation:

Let's take a look at the attached picture. Now

The total voltage across both capacitors is the same as the sum of the voltage from each device, that statement is true for any electrical device connected in series. So a) is TRUE

The equivalent capacitance is going to be: \frac{1}{C_{total}}=\frac{1}{C_1} +\frac{1}{C_2}

And that value can be mathematically proven that is always less than any of the values of each capacitor. So b is TRUE

And through both capacitors flow the same current, but the amount of charge depends on the value of the capacitors, so only could be the same if the capacitors are the same value. Otherwise, don't. C) not always, so FALSE

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stealth61 [152]

Answer:

7160.2812 s or 1.988 hours

Explanation:

m = Mass of person

R = Radius of Earth = 6.37\times 10^{6}\ m

g = Acceleration due to gravity = 9.81 m/s²

\omega = Angular speed

Force at equator would be

F_e=m(g-\omega^2R)

Force at pole

F_p=mg

From the question

F_e=\dfrac{1}{2}F_p\\\Rightarrow m(g-\omega^2R)=\dfrac{1}{2}F_p\\\Rightarrow \omega=\sqrt{\dfrac{g}{2R}}

Time period is given by

T=\dfrac{2\pi}{\omega}\\\Rightarrow T=2\pi\sqrt{\dfrac{2R}{g}}\\\Rightarrow T=2\pi\sqrt{\dfrac{2\times 6.37\times 10^6}{9.81}}\\\Rightarrow T=7160.2812\ s=1.988\ hours

The rotational period of the planet is 7160.2812 s or 1.988 hours

5 0
3 years ago
A walkman uses four standard 1.5 V batteries. How much resistance is in the circuit if it uses a current of 0.02A? *
hodyreva [135]

Answer:

75ohms

Explanation:

V= IR

V = 1.5volts

I = 0.02A

1.5 = 0.02×R

Making R the subject

R = 1.5/0.02

R = 75ohms

The resistance in the circuit will be 75ohms

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28. Multiple-Concept Example 5 reviews many of the concepts that play roles in this problem. An extreme skier, starting from res
Maksim231197 [3]

Answer: 7.78m/s

Explanation: As the the skier slide down the height, we assume the motion of a body, slidind down an incline plane.

Force down the plane= [email protected]

Frictional force= umg

u= coefficient of friction

Net force on skier = [email protected] umg

ma = [email protected]

a = g([email protected] - u) = 9.8 (sin 25- 0.2)

a = 9.8 × (0.4226-0.2) = 9.8 × 0.2226

a = 2.18m/s²

Using the formula V² = U² + 2aH

Where H = (10.4+ 3.5)=total height of descent before landing, U= 0.

V = √ 2 × 2.18× 13.9 = √60.604

V = 7.78m/s

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