I believe the answer is 4 carbons. Glycolysis involves break down of glucose to two molecules of pyruvic acid (3 carbons) under aerobic conditions. At the end of glycolysis the two pyruvate molecules undergoes pyruvate oxidation to capture the remaining energy in the form of ATP. A carboxyl group is removed from pyruvate and released in the form carbon dioxide, leaving a two carbon molecule which forms Acetyl-CoA (2 molecules). Acetyl-CoA then serves as a fuel for the citric acid cycle in the next stage of cellular respiration.
Answer:
16.4 °C
Explanation:
Boiling point elevation is the phenomenon in which the boiling point of a solvent will increase when another compound is added to it; meaning that athe resultant solution has a higher boiling point than its pure solvent.
Using the ebullioscopic constant,
ΔT = m * i * Kb
Where,
Δ T is the temperature difference between the boiling point of the solution, Temp.f and boiling point of the pure solvent, Temp.i
Kb is the ebulliscope factor of water = 0.510 °C.kg/mol
i is the van hoffs number = 1
m is the molality in mol/kg.
Calculating the molality of the solution,
Temp.i = 100°C
Temp.f = 104.5 °C
= 4.5/(1*0.510)
= 8.8235 mol/kg
Freezing point depression is defined as the decrease in the freezing point of a solvent on the addition of a solute.
Using the same equation, but kf = 1.86 °C.kg/mol
ΔT = m * i * Kf
Temp.i = freezing point of water = 0°C
Temp.f = (8.8235*1.86) - 0
= 16.412 °C
Freezing point of the solution = 16.4 °C
<h2>Answer:</h2>
<em>Third option is correct, 7.5 grams of CuI.</em>
<h3>Explanation:</h3>
Given data :
Mass of copper = 10 grams
Mass of iodine = 10 grams
theoretical yield of copper iodide = ?
Solution:
Moles of Cu: 10 / 63.5 = 0.157 mol.
Moles of I2: 10 / 254 = 0.039 mol.
Equation : 2Cu + I2 → 2CuI
Limiting reactant : I2
So Moles of CuI produced = 0.039 mol.
Mass of CuI = 0.039 mol * 190.5 = around 7.5g
Answer:
Explanation:
Saturated hydrocarbons are defined as the hydrocarbons in which a single bond is present between carbon and carbon atoms.These are called as alkanes. The general formula for these hydrocarbons is
Unsaturated hydrocarbons are defined as the hydrocarbons which have double or triple covalent C-C bonds. They are known as alkenes and alkynes respectively. The general formula for these hydrocarbons is and .
1. Propyne is and is an unsaturated hydrocarbon.
2. Methane is and is a saturated hydrocarbon
3. Nonane is is a saturated hydrocarbon.
4. Methyl is and is a saturated alkyl group.