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3 years ago

How are elements classified organized?

Chemistry

1 answer:

rodikova [14]3 years ago

3 0

They’re put in groups that have similar properties to them. but the periodic table is organized by atomic numbers.

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If the ph of a solution is 6.2 what would the poh be

horsena [70]

PH + poH = 14
6.2 +poH = 14
poH = 7.8

7 0

4 years ago

Read 2 more answers

The prefix mili-means a thousand

OLEGan [10]

<h2>Answer:</h2>

<em>Given data:</em>

1 kilogram = 1,000 grams

how many kilograms is 1,216 grams?

<em>Solution:</em>

1000 grams = 1 kilogram

1 gram = 1/1000 kilograms

1216 grams = 1/1000 * 1216 = 1.216 kilograms.

<em> Hence 1216 grams = 1.216 kilograms.</em>

3 0

3 years ago

The element iodine would be expected to form covalent bond(s) in order to obey the octet rule. Use the octet rule to predict the

zhannawk [14.2K]

Answer:

HI (hydrogen iodide).

Explanation:

Hello,

In this case, since iodine is in group VIIA, it has seven valence electrons at its outer shell, which means that it only needs one bond to attain the octet. Moreover, since hydrogen has just one electron at its outer shell, one hydrogen turns out enough to obey the octet when hydrogen and iodine bond as shown below:

$H-I$

Therefore, the required formula is:

$HI$

Which is hydrogen iodide.

Best regards.

7 0

3 years ago

15. A substance that has a melting point of 1074 K

inna [77]

Answer:

Ionic solid.

Explanation:

Ionic solid dissociated into free ions capable of conducting electricity in aqueous solution. Ionic solids are also characterised by high melting point due to strong ionic bonds. No free ions or electrons to conduct electricity in solid form.

3 0

3 years ago

consider the reaction between calcium oxide and carbon dioxide: cao ( s ) + co 2 ( g ) → caco 3 ( s ) a chemist allows 14.4 g of

lana [24]

Answer:

Explanation:

Given data:

Mass of calcium oxide = 14.4 g

Mass of carbon dioxide = 13.8 g

Actual yield of calcium carbonate = 19.4 g

Mass of calcium carbonate produced = ?

Limiting reactant = ?

Percent yield = ?

Chemical equation:

CaO + CO₂ → CaCO₃

Number of moles of CaO:

Number of moles of CaO = Mass /molar mass

Number of moles of CaO = 14.4 g / 56.1g/mol

Number of moles of CaO = 0.26 mol

Number of moles of CO₂:

Number of moles of CO₂= Mass /molar mass

Number of moles of CO₂ = 13.8 g / 44 g/mol

Number of moles of CO₂ = 0.31 mol

Now we will compare the moles of CaCO₃ with CO₂ and CaO.

CaO : CaCO₃

1 : 1

0.26 : 0.26

CO₂ : CaCO₃

1 : 1

0.31 : 0.31

The number of moles of CaCO₃ produced by CaO are less it will be limiting reactant.

Limiting reactant:

CaO

Theoretical yield:

Mass of CaCO₃ = moles × molar mass

Mass of CaCO₃ = 0.26 mol × 100 g/mol

Mass of CaCO₃ = 26 g

Percent yield:

Percent yield = Actual yield / theoretical yield × 100

Percent yield = 19.4 g/ 26 g× 100

Percent yield = 74.6 %

3 0

3 years ago