Assuming 100% dissociation of K3PO4 you get each molecule of K3 PO4 dissociates into four particles: 3 K4 cations and 1 PO4 - anion. That means that Van't Hoff factor, i, is 4. i = 4. So, the decrease in freezing point of the water solution is Delta Tf = i * Kf * m. Where Kf is the molal cryoscopic constant of water = 1.86 °C /m; and the molality m = 2.59 m => Delta Tf = 4 * 1.86 °C / m * 2.59 m = 19.3 °C. And the freezing point is the normal freezing points less 19.3°C = 0°C - 19.3°C = - 19.3°C. The increase in the boiling point Delta Tb = i * kb * m = 4 * 0.512 °C /m * 2.59 m = 5.3°C => <span>Tb = normal boiling point + 5.3°C = 100°C + 5.3°C = 105.3°C.</span>
The solution to your problem is as follows:
<span>2 KClO3 → 2 KCl + 3 O2
</span><span>MW of KCL = 39.1 + 35.35 = 74.6 g/mole
62.6/74.6 = 0.839 moles KCl produced
0.839 moles KCl x 3O2/2KCl x 32g/mole O2 = 40.27g of O2 was produced
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Therefore, there are <span>40.27g of O2 produced during the reaction.
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I hope my answer has come to your help. Thank you for posting your question here in Brainly.
Mass of water added:
0.997 x 1500
= 1495.5 grams
a) Volume = mass / density
Volume = 1495.5 / 0.917
Volume = 1630 cm³ = 1.63 L
b) The ice cannot be contained in the bottle as its volume exceeds that of the bottle.
I think the correct answer from the choices listed above is option 1. It would be the molecule carbon disulphide that will be polar, based on the structure of the choices given. Hope this answers the question. Have a nice day. Feel free to ask more questions.
Answer:
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