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laiz [17]
3 years ago
5

Sunlight above the Earth's atmosphere has an intensity of 1.36 kW/m2. If this is reflected straight back from a mirror that has

only a small recoil, the light's momentum is exactly reversed, giving the mirror twice the incident momentum. (a) Calculate the force per square meter of mirror (in N/m2). N/m2 (b) Very low mass mirrors can be constructed in the near weightlessness of space, and attached to a spaceship to sail it. Once done, the average mass per square meter of the spaceship is 0.170 kg. Find the acceleration (in m/s2) of the spaceship if all other forces are balanced. m/s2 (c) How fast (in m/s) is it moving 24 hours later
Physics
1 answer:
galina1969 [7]3 years ago
8 0

Answer:

a)  F=9.2*10^{-6}N/m^2

b)  a=5.4*10^{-4}m/s

c)  v=46.65m/s

Explanation:

From the question we are told that:

Intensity I= 1.36 kW/m2=>1360W/m

b)Average mass per square meter m = 0.170 kg

c) T=24hrs

a)

Generally the equation for force per square meter  is mathematically given by

F=\frac{2E}{C}

F=\frac{2*1360}{3*10^8}

F=9.2*10^{-6}N/m^2

b)

Generally the equation for force  is mathematically given by

F=ma

Therefore

a=\frac{F}{m}

a=\frac{9.2*10^{-6}N/m^2}{0.0170}

a=5.4*10^{-4}m/s

c)

Generally the Newton's equation for Motion is mathematically given by

v=u+at

v=0+5.4*10^{-4}m/s*(24*3600)

v=46.65m/s

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Define any two characteristics of sound​
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A 126- kg astronaut (including space suit) acquires a speed of 2.70 m/s by pushing off with her legs from a 1800-kg space capsul
jeka94

The change in the speed of the space capsule will be -0.189 m/s.

The average force exerted by each on the other will be 567 N.

The kinetic energy of each after the push for the astronaut and the capsule are 459.27 J and 32.14 J.

<h3>Given:</h3>

Mass of the astronaut, m_a = 126 kg

Speed he acquires, v_{a}  = 2.70 m/s

Mass of the space capsule, m_{c} = 1800kg

The initial momentum of the astronaut-capsule system is zero due to rest.

P_f = m_av_a + m_cv_c

P_I = 0

m_av_a + m_cv_c = 0

v_c =\frac{- m_a v_a}{m_c}}\\\\

   = \frac{126* 2.70}{1800}

   = - 0.189 m/s

Therefore,

According, to the impulse-momentum theorem;

FΔt = ΔP

ΔP = m Δv

ΔP = 126×2.70

    = 340.2 kgm/sec

t is time interval = 0.600s

F = ΔP/Δt

F = 340.2/0.600

  = 567 N

Therefore, the average force exerted by each on the other will be 567 N.

The Kinetic Energy of the astronaut;

K.E = \frac{1}{2} m v^2

     = \frac{1}{2} × 126 × (2.70) ^2

     = 459.27 J

The Kinetic Energy of the capsule;

K.E = \frac{1}{2} m v^2

     = \frac{1}{2}×1800×(0.189) ^2

     = 32.14 J

Therefore, the kinetic energy of each after the push for the astronaut and the capsule are 459.27 J and 32.14 J.

Learn more about kinetic energy here:

brainly.com/question/26520543

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Arace car accelerates uniformly at 11.3 m/s2. If the race car starts from rest how fast will it
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75.71 m/s

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Making v the subject of the above formula

v=at+u

Substituting 6.7 s for time, t and 11.3 for a and taking u as zero since it starts from rest

v=11.3*6.7=75.71 m/s

7 0
3 years ago
Are colavent bonds more likely to be found in compounds contaning both materals and nonmetals or compounds contaning only nonmet
atroni [7]

Answer:

bonds between 2 alike atoms or most non-metals get a covalent bond when reacting to the ... It tells what kinds of atomas are in a compound and how many.

Hope this helped

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