Answer:
1.5 * 10^-2 Tm^2
Explanation:
Electric Flux = B.A cos(theta)
B = 0.055 T
A = 0.32 m^2
theta = 30
Electric Flux = (0.055 T).(0.32 m^2).Cos(30) = 0.0152 = 1.5 * 10^-2 Tm^2
Answer:
The correct answer is
d. heating evaporative cooling and mineral transport
Explanation:
Plants transpire to expel excess heat energy by a process known as evaporative cooling. As the water involved in transpiration evaporates, heat energy is transferred from the plant system into the surrounding environment cooling down the plant.
During transpiration, the stomata of the plant are open allowing the outward flow of the evaporated water and also the open stomata enable the plant to absorb carbon dioxide (CO2) from the atmosphere. The carbon dioxide is required in photosynthesis for the formation glucose while producing oxygen as well.
The water also transports nutrients dissolved in it as it is being transported to the leafs for evaporation. These nutrients are thus delivered tm all parts of the plant.
Answer:
The temperature coefficient of resistivity for a linear thermistor is 
Explanation:
Given that,
Initial temperature = 0.00°C
Resistance = 75.0 Ω
Final temperature = 525°C
Resistance = 275 Ω
We need to calculate the temperature coefficient of resistivity for a linear thermistor
Using formula for a linear thermistor
Put the value into the formula
Hence, The temperature coefficient of resistivity for a linear thermistor is
