Okay so here's the approach I took:
The potential difference in each of the circuits must be the same so if we derive equations for both the potential differences we can set them equal to each other and solve for R1:
In the first circuit
V = 2.2(R1)
In the second we have to find the equivalent resistor, since they are connected in series:
1/R1 + 1/R2 + 1/R3... = Rt
We have R2 so...
1/R1 + 1/3.1 = Rt
1/R1 + 0.323 = Rt
So...
V = 1.4(1/R1 + 0.323)
Set those equal:
2.2R1 = 1.4(1/R1 + 0.323)
2.2R1 = 1.4(1/R1) + 0.4522
Now multiply everything by R1 so we can combine like terms:
2.2R1^2 = 1.4 + 0.4522R1
Isolate to form a quadratic
2.2R1^2 - 0.4522R1 - 1.4 = 0
Solving this quadratic:
R1 = 0.90708 or R1 = -0.701
Since R cannot be negative
R1 = 0.907 ohms
Answer:
The kite string is feet long.
Explanation:
Use the Pythagorean Theorem, which is .
Here the question is asking for , which would be the hypotenuse, or the longest side of the triangle.
So the would be , and the would be .
Plug those values into the formula, and that would get .
Now, solve for , which would equal .
That means we would have to solve for .
Square root both sides of the equation, getting .
Solve for , which would get us .
Hence, the answer to this would question would be .
<h2><u><em>
PLEASE MARK AS BRAINLIEST!!!!!</em></u></h2>
<span>It's continuous except for a pair of dark lines.
They are very close together in the yellow/orange section of the spectrum.</span>
The voltage at the end of the conductors is 12V
<u>Explanation:</u>
Given:
Resistance, R = 12Ω
Heat released, H = 144J
Time, t = 12s
Voltage, V = ?
According to joule's law:
H = I²RT
where,
I is the current
T is the time
R is the resistance
The above formula can also be written as:
where,
V is the voltage
On substituting the value in the formula we get:
Therefore, the voltage at the end of the conductors is 12V