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jeka57 [31]
3 years ago
6

Please Help!!! For A&B

Physics
1 answer:
klio [65]3 years ago
5 0

Answer:

A. 40N

B. 5m/s

Explanation:

A.

Impulse is equal to the area under the curve of a force vs. time graph. In this case, the area is in the shape of a triangle with base 8 (12-4=8) and perpendicular height 10:

<em>Area of a triangle = (1/2)bh</em>

A=(1/2)*8*10

=40

ANSWER: 40N

B.

<em>Impulse = mass * velocity</em>

40 = 8v

v = 5

ANSWER: 5m/s

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7 0
3 years ago
Two equipotential surfaces surround a +3.10 x 10-8-c point charge. how far is the 290-v surface from the 41.0-v surface?
MrMuchimi
 T<span>he equation to be used here to determine the distance between two equipotential points is:
V = k * Q / r 

where v is the voltage of the point, k is a constant, Q is charge of the point measured in coloumbs and r is the distance. 
In this case, we can use ratio of proportions to determine the distance between the two points. in this respect, 

Point 1: 
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Point 2:
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R = k*Q/41
from equation 10 kQ = 290r
R = 290/(41)= 7.07 m 
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