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2 years ago

Please Help!!! For A&B

Physics

1 answer:

klio [65]2 years ago

5 0

Answer:

A. 40N

B. 5m/s

Explanation:

Impulse is equal to the area under the curve of a force vs. time graph. In this case, the area is in the shape of a triangle with base 8 (12-4=8) and perpendicular height 10:

<em>Area of a triangle = (1/2)bh</em>

A=(1/2)*8*10

=40

ANSWER: 40N

<em>Impulse = mass * velocity</em>

40 = 8v

v = 5

ANSWER: 5m/s

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She changed a closed circuit to an open circuit

Explanation:

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The plastic jars of the air capacitor represent the parallel conducting plates.

<h3>What is Air capacitor?</h3>

Air capacitor is a type of capacitor that uses air as its dielectric. The simplest air capacitors will contain two conductive plates separated by an air gap.

This capacitor stores and releases electricity in the circuit using;

air as the electrical source,
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the plastic jar as the parallel conducting plates.

Thus, the plastic jars of the air capacitor represent the parallel conducting plates.

Learn more about air capacitor here: brainly.com/question/15755974

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1 year ago

A force of 5.00 N to the left causes a 1.35 kg book to have a net acceleration of 0.76 m/s2 to the left. What is the frictional

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Answer:

4.0 N

Explanation:

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2 years ago

A 4.4 nC charge exerts a repulsive force of 36 mN on a second charge which is located

zhenek [66]

The magnitude and sign of the second charge will be + 8.6241×10⁻¹⁹ C. The principal of the Columb's law is used in the given problem.

<h3>What is Columb's law?</h3>

The force of attraction between two charges, according to Coulomb's law, is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

Charges that are similar repel each other, whereas charges that are diametrically opposed attract each other.

They will repel, moving in opposite directions at the same speed. Because the magnitude and nature of the charge are the same.

The given data in the problem is;

q₁ is the charge 1 = 4.4 nC = 4.4 ×10⁻⁹ C

F is the repulsive force = 36 mN =36 ×10⁶ N

d is the distance = 0.70 m

The Coulomb force is found as;

$\rm F = \frac{Kq_1q_2}{r^2}\\\\\ \rm 36\times 10^6 = \frac{9 \times 10^9 }{(0.7)^2} \times 4.4 \times 10^{-9} \times q_2\\\\\ q_2 = 8.6241 \times 10^{-19 } \ C$