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3 years ago

How many total atoms are in 0.170 g of p2o5?

1 answer:

3 0

7.20594 x 10^20

First you must determine how many moles of P3O5 you have. This is done by using the formula
Number of moles (n) = mass in grams of substance (m) /divided by/ Molar mass (M) [this is the sum of the atomic mass of all atoms in the compound]

n = 0.170 / P (31 x 2) + O (16 x 5)
n = 0.170 / 142
n = 0.001197 moles

Then you use avagadros number 6.02 x10^23 this is the number of atoms in one mole of any substance. Since you have 0.001197 moles you multiply the number of moles by avagadros number

0.001197 x (6.02 x 10^23)
= 7.20594 x 10^20 atoms

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A student is given a 2.002 g sample of unknown acid and is told that it might be butanoic acid, a monoprotic acid (HC4H7O2, equa

Elina [12.6K]

Answer: The identity of the unknown acid is butanoic acid or ascorbic acid.

Explanation:

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in L)}}$

Molarity of NaOH solution = 0.570 M

Volume of solution = 39.55 mL

Putting values in above equation, we get:

$0.570M=\frac{\text{Moles of NaOH}\times 1000}{39.55}\\\\\text{Moles of NaOH}=\frac{0.570\times 39.55}{1000}=0.0225mol$

The chemical equation for the reaction of NaOH and monoprotic acid follows:

$NaOH+HX\rightarrow NaX+H_2O$

By Stoichiometry of the reaction:

1 mole of NaOH reacts with 1 mole of HX

So, moles of monoprotic acid = 0.0225 moles

The chemical equation for the reaction of NaOH and diprotic acid follows:

$2NaOH+H_2X\rightarrow 2NaX+2H_2O$

By Stoichiometry of the reaction:

2 moles of NaOH reacts with 1 mole of diprotic acid

So, moles of diprotic acid = $\frac{0.0225}{2}=0.01125moles$

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

For butanoic acid:

Mass of butanoic acid = 2.002 g

Molar mass of butanoic acid = 88 g/mol

Putting values in above equation, we get:

$\text{Moles of butanoic acid}=\frac{2.002g}{88g/mol}=0.02275mol$

For L-tartaric acid:

Mass of L-tartaric acid = 2.002 g

Molar mass of L-tartaric acid = 150 g/mol

Putting values in above equation, we get:

$\text{Moles of L-tartaric acid}=\frac{2.002g}{150g/mol}=0.0133mol$

For ascorbic acid:

Mass of ascorbic acid = 2.002 g

Molar mass of ascorbic acid = 176 g/mol

Putting values in above equation, we get:

$\text{Moles of ascorbic acid}=\frac{2.002g}{176g/mol}=0.01137mol$

As, the number of moles of butanoic acid and ascorbic acid is equal to the number of moles of acid getting neutralized.

Hence, the identity of the unknown acid is butanoic acid or ascorbic acid.

5 0

3 years ago

What is the potential energy of the bowling ball as it sits on top of the building?

Tju [1.3M]

Answer:

Potential energy is energy due to an object's height above the ground.

Potential energy = mass x gravity x height

Kinetic energy is energy due to the motion of the object.

Kinetic energy = 1/2 x mass x velocity²

8 0

3 years ago

what does NaBr + Ca(OH)2 -> CaBr2 + NaOH make, what rection for an example rust. is it aa chemical reaction? please reply asa

Semenov [28]

FORMULA FOR RUST IS FE2O3.XH20

3 0

3 years ago

Read 2 more answers

iron has a density of 7.86 g cm3 could a block of metal with a mass of 18.2 and a volume of 2.56 cm^3 be iron?

satela [25.4K]

The density of the block will be "7.11 gm/cm³". A further explanation is provided below.

Given values are:

Density of iron,

$7.86 \ g/cm^3$

Mass of block of metal,

$18.2 \ gm$

Volume of block,

$2.56 \ cm^3$

By using the formula,

→ $Density = \frac{Mass}{Volume}$

then,

→ The density of block will be:

= $\frac{Mass}{Volume}$

= $\frac{18.2}{2.56}$

= $7.11 \ gm/cm^3$

Learn more:

brainly.com/question/10804879

7 0

2 years ago

g modenr vacuum pumps make it easy to attain pressures of the order of in the laboratory. at a preasusure of 6.75 atm and an ord

Ratling [72]

Answer:

Number of molecules = 1.8267×10^20

Explanation:

From the question, we can deuced that the gases behave ideally, the we can make use of the ideal gas equation, which is expressed below;

PV = nRT

where

P =pressure

V =volume

n = the number of moles

R is the gas constant equal to 0.0821 L·atm/mol·K

T is the absolute temperature

Given:

P = 6.75 atm;

T = 290.0 k,

; V = 1.07 cm³ = 0.001 L

( 6.75 atm)(0.00107 L) = n(0.0821 L·atm/mol·K)(290K)

n = 3.0335167*10^-4 moles

But there are 6.022×10²³ molecules in 1 mole,

Number of molecules = 1.8267×10^20

7 0

3 years ago